问题
I'm familiar with vertex and fragment shaders but still confused about how a fragment shader determines the amount of fragments from the output of vertex shader.
If I have 3 vertices and I draw a triangle primitive in GLSL, then vertex shader will run three times for every vertex and then fragment shader will run many times (depending upon the number of fragments, once for each fragment).
I want to know how fragment shader determines the fragments? Does it use gl_Position? If I don't set gl_Position in my vertex shader does fragment shader still be able to generate fragments or not?
Is gl_Position is compulsory to set every time in vertex shader?
回答1:
You're talking about the step in rasterization known as scan-conversion. The GPU takes the positions generated by your vertex shader and interpolates their attributes to produce the fragments that are passed to your fragment shader. So yes, it is essential for you to set gl_Position in the vertex shader.
After converting the coordinates of a triangle to window coordinates, scan conversion takes the triangle and breaks it up based on the arrangement of window pixels over the output image that the triangle covers. Source.
来源：https://stackoverflow.com/questions/27069881/how-fragment-shader-determines-the-number-of-fragments-from-vertex-shader-output