How make this eav query to make horizontal result

丶灬走出姿态 提交于 2019-12-06 04:37:28

问题


The case:

tables:

product:
product_id|name        |
------------------------
1         |iphone 4    |
2         |gallaxy 2   |
3         |blackbery 6 |

product_attribute:

id|product_id|attribute_id
--------------------------------------------------
 1 |1        |2
 2 |1        |6
 .    .        .

attribute:
------------------------------
attribute_id|name  |value|
        1   |width |300
        2   |width |320
        3   |width |310
        4   |height|390
        5   |height|370
        6   |height|380

should get result:

product_id|height|width
 1        |380   |320
 ......................

Edit: height and width attributes its only part of product attributes - product need to have dynamic ability to be added by the user in backend as it done in magento, because that i choose eav db design. Please write queries if it possible in case we dont know which names product have.

Thanks


回答1:


There are several ways to implement this. Something like this should work joining back on the table multiple times for each attribute value:

SELECT p.product_id,
    a.value height,
    a2.value width
FROM Product p
    JOIN Product_Attribute pa ON p.product_id = pa.product_id 
    JOIN Attribute a ON pa.attribute_id = a.attribute_id AND a.name = 'height'
    JOIN Product_Attribute pa2 ON p.product_id = pa2.product_id 
    JOIN Attribute a2 ON pa2.attribute_id = a2.attribute_id AND a2.name = 'width'

And here is the Fiddle.

Here is an alternative approach using MAX and GROUP BY that I personally prefer:

SELECT p.product_id,
    MAX(Case WHEN a.name = 'height' THEN a.value END) height,
    MAX(Case WHEN a.name = 'width' THEN a.value END) width
FROM Product p
    JOIN Product_Attribute pa ON p.product_id = pa.product_id 
    JOIN Attribute a ON pa.attribute_id = a.attribute_id 
GROUP BY p.product_id

Good luck.




回答2:


One approach is to use correlated subqueries in the SELECT list, although this can be less than optimum for performance on large sets. For retrieving just a few rows rows from the product table, it won't be bad. (You'll definitely want appropriate indexes.)

SELECT p.product_id
     , ( SELECT a1.value
           FROM attribute a1
           JOIN product_attribute q1
             ON q1.attribute_id = a1.attribute_id
          WHERE q1.product_id = p.product_id
            AND a1.attribute_name = 'height'
          ORDER BY a1.id
          LIMIT 0,1
       ) AS height_1
     , ( SELECT a2.value
           FROM attribute a2
           JOIN product_attribute q2
             ON q2.attribute_id = a2.attribute_id
          WHERE q2.product_id = p.product_id
            AND a2.attribute_name = 'width'
          ORDER BY a2.id
          LIMIT 0,1
       ) AS width_1
  FROM product p
 WHERE p.product_id = 1

This query will return the row from product, along with the values of the attributes, if they exist. If the attribute values are not found, the query will return a NULL in place of the attribute value. (This differs from the behavior of a query that uses INNER JOIN in place of correlated subquery... where a "missing" row from the attribute or product_attribute table would filter out the row from product being returned.)

The purpose of the LIMIT clauses is to guarantee that the subqueries will return not return more than one row. (If a subquery in the SELECT list were return more than one row, MySQL would return an error.) The purpose of the ORDER BY is to make the query deterministic, again, in the event there is more than one row that satisfies the subquery. (Absent the ORDER BY clause, when there is more than one row, MySQL is free to arbitrarily return whichever row it chooses to.)

For "multi-valued" attributes, the same approach works. We just add more subqueries, but specify LIMIT 1,1 to return the second attribute value, LIMIT 2,1 to return the third value, etc.


(Oh, the joy of an EAV model implemented in a relational database.)


Followup:

Q: "... more general case as it happen in eav db that we dont know before which attributes names we have."

A: The relational model is based on the principle that a tuple contains a specified number of columns, of a specified type.

What you are (apparently) trying to do is return a variable number of columns when you run a query. A SELECT statement includes a specific list of expressions to be returned; this cannot vary and the datatypes of the values returned by each expression does not vary from row to row.

The query above returns one instance of a "height" attribute value, and one instance of a "width" attribute value, for each product.

For a more "more general case", we would really expect that each attribute value would be returned on its own separate row.

The more general query, if you don't know "ahead of time" what attributes are associated with a product would be:

SELECT p.product_id
     , a.attribute_id
     , a.name         AS attribute_name
     , a.value        AS attribute_value
  FROM product p
  LEFT
  JOIN product_attribute q
    ON q.product_id = p.product_id
  LEFT
  JOIN attribute a
    ON a.attribute_id = q.attribute_id
 WHERE p.product_id = 1
 ORDER
    BY p.product_id
     , a.name
     , a.attribute_id

That will return a resultset which can easily be processed:

product_id attribute_id attribute_name attribute_value
---------- ------------ -------------- ---------------
         1            6 height         380
         1            2 width          320

Q: "looks like should be done in 2 stages: 1. get all attributes names for product 2.then your code with server side code of attributes names in for loop"

A: No, it looks like a single query will return all the attribute name and value pairs for a product. Each attribute name/value will be on a separate row.

There's no need to use a "for loop" to generate additional queries against the database. Yes, it's possible to do that, but totally unnecessary.

If you have some bizarre requirement to compose another query to run against the database to return the resultset in the format you specified, whatever processing you would do to process the resultset from the "more general case" statement, it would probably be more efficient to just process the resultset, without running any more queries against the database.

If you need to return a resultset that looks like this:

 product_id height width
 ---------- ------ -----
          1 380    320

(as bizarre a requirement as that is, to compose another query) it's entirely possible to use that resultset from the "more general query" to generate a query that looks like this:

SELECT 1 AS product_id, '380' AS height, '320' AS width

Though such an exercise is rather pointless, given that you aren't returning any new information you didn't return previously, and now you have another resultset that you need to process, which just seems to me to be a boatload of unnecessary overhead.




回答3:


Let me first say this is a really poor design. Under your current approach, you will need to run multiple subqueries or joins with table aliases to achieve the result you want.

SELECT 
    product_id,
    (
        SELECT product_attribute.value 
        FROM product_attribute, attribute 
        WHERE product_attribute.product_id=product.product_id 
        AND product_attribute.attribute_id=attribute.attribute_id
        AND product_attribute.name = 'width'
    ) AS 'width',
    (
        SELECT product_attribute.value 
        FROM product_attribute, attribute 
        WHERE product_attribute.product_id=product.product_id 
        AND product_attribute.attribute_id=attribute.attribute_id
        AND product_attribute.name = 'height'
    ) AS 'height'
FROM
    product
ORDER BY 
    ...      

Let me suggest:

attribute
   attribute_sid  (eg, string id)

product
   product_id
   name
   ...

product_attribute
   product_id   (foreign key to product table)
   attribute_sid  (foreign key to attribute table)
   value   

This way, you have a definitive list of attributes, and a single attribute value per product.

SELECT attribute_sid, value FROM product_attribute WHERE product_id = 1

... will retrieve all the attributes and values, which can conveniently be placed in a dict, array, or map.



来源:https://stackoverflow.com/questions/14740758/how-make-this-eav-query-to-make-horizontal-result

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