“times 510-($-$$) db 0” does not work

穿精又带淫゛_ 提交于 2019-12-06 04:09:11
Michael Petch

I don't believe there is anything wrong with times 510-($-$$) db 0. It seems to me your are attempting to find the proper way to access the variable the_secret and then display it to the screen. I'll provide one mechanism based on this attempt which has the most promise:

mov al, [the_secret];
int 0x10;

If you set up DS properly, set an origin point using org 0x7c00 and make sure BH is set to the page number you want to write to (you want 0) then the following code should work:

[bits 16]          ; 16-Bit code
[org 0x7c00]       ; Set the origin point to 0x7c00

start:
    xor ax,ax      ; We want a segment of 0 for DS for this question
    mov ds,ax      ;     Set AX to appropriate segment value for your situation
    mov es,ax      ; In this case we'll default to ES=DS
    mov bx,0x8000  ; Stack segment can be any usable memory

    mov ss,bx      ; This places it with the top of the stack @ 0x80000.
    mov sp,ax      ; Set SP=0 so the bottom of stack will be @ 0x8FFFF

    cld            ; Set the direction flag to be positive direction

    mov ah, 0x0e
    mov al, [the_secret]  ; al = character from memory DS:[the_secret]
    xor bh, bh            ; bh = 0 = video page number
    int 0x10;

    jmp $

the_secret:;
    db 'X';

times 510-($-$$) db 0
dw 0xAA55

The start up code sets DS to zero since we set an origin point of 0x7c00. The bootloader is loaded at 0x0000:0x7c00 (physical address 0x07c00). This ensures accessing the variable the_secret will be done properly. mov al, [the_secret] is the equivalent of saying mov al, ds:[the_secret]. If the DS segment register is not set properly, and the origin point isn't set properly, the memory access will not read from the proper location.

INT 0x10/AH=0x0E requires a page number to be set. The first video display page is 0, BH should be set accordingly.

More on the other setup instructions can be found in my StackOverflow answer that contains General Bootloader Tips.

The code I have presented should display X to the console if properly written to a disk image.


To assemble this code and produce a disk image (in my example a 720k floppy):

nasm -f bin bootload.asm -o bootload.bin
dd if=/dev/zero of=disk.img bs=1024 count=720
dd if=bootload.bin of=disk.img bs=512 count=1 conv=notrunc

The first command does the assembling of bootload.asm into a flat binary file called bootload.bin. The second command produces a zero filled disk image (disk.img) of size 1024 * 720 (720kb floppy), and the last command copies 512 bytes of data from bootload.bin to the first sector of the disk image. conv=notrunc tells DD not to truncate the file after writing. If you were to leave that off disk.img would be 512 bytes long after the bootsector was written.

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