I am trying to find a mongoDB script which will look at a collection where there are multiple records of the same document and only provide me with the latest version of each document as a result set.
I cannot explain it in English any better than above but maybe this little SQL below might explain it further. I want each document by transaction_reference
but only the latest dated version (object_creation_date
).
select
t.transaction_reference,
t.transaction_date,
t.object_creation_date,
t.transaction_sale_value
from MyTable t
inner join (
select
transaction_reference,
max(object_creation_date) as MaxDate
from MyTable
group by transaction_reference
) tm
on t.transaction_reference = tm.transaction_reference
and t.object_creation_date = tm.MaxDat
The reason why there are multiple versions of the same document is because I want to store each iteration of a transaction. The first time I receive a document, it may be in transaction_status
of UNPAID then I receive the same transaction again and this time the transaction_status
is PAID.
Some analysis will be to SUM all unique transactions whereas some other analysis may be to measure the time distance between a document with status UNPAID and the next of PAID.
As per request, here are two documents:
{
"_id": {
"$oid": "579aa337f36d2808839a05e8"
},
"object_class": "Goods & Services Transaction",
"object_category": "Revenue",
"object_type": "Transaction",
"object_origin": "Sage One",
"object_origin_category": "Bookkeeping",
"object_creation_date": "2016-07-05T00:00:00.201Z",
"party_uuid": "dfa1e80a-5521-11e6-beb8-9e71128cae77",
"connection_uuid": "b945bd7c-7988-4d2a-92f5-8b50ab218e00",
"transaction_reference": "SI-1",
"transaction_status": "UNPAID",
"transaction_date": "2016-06-16T00:00:00.201Z",
"transaction_due_date": "2016-07-15T00:00:00.201Z",
"transaction_currency": "GBP",
"goods_and_services": [
{
"item_identifier": "PROD01",
"item_name": "Product One",
"item_quantity": 1,
"item_gross_unit_sale_value": 1800,
"item_revenue_category": "Sales Revenue",
"item_net_unit_cost_value": null,
"item_net_unit_sale_value": 1500,
"item_unit_tax_value": 300,
"item_net_total_sale_value": 1500,
"item_gross_total_sale_value": 1800,
"item_tax_value": 300
}
],
"transaction_gross_value": 1800,
"transaction_gross_curr_value": 1800,
"transaction_net_value": 1500,
"transaction_cost_value": null,
"transaction_payments_value": null,
"transaction_payment_extras_value": null,
"transaction_tax_value": 300,
"party": {
"customer": {
"customer_identifier": "11",
"customer_name": "KP"
}
}
}
and second version where it is paid now
{
"_id": {
"$oid": "579aa387f36d2808839a05ee"
},
"object_class": "Goods & Services Transaction",
"object_category": "Revenue",
"object_type": "Transaction",
"object_origin": "Sage One",
"object_origin_category": "Bookkeeping",
"object_creation_date": "2016-07-16T00:00:00.201Z",
"party_uuid": "dfa1e80a-5521-11e6-beb8-9e71128cae77",
"connection_uuid": "b945bd7c-7988-4d2a-92f5-8b50ab218e00",
"transaction_reference": "SI-1",
"transaction_status": "PAID",
"transaction_date": "2016-06-16T00:00:00.201Z",
"transaction_due_date": "2016-07-15T00:00:00.201Z",
"transaction_currency": "GBP",
"goods_and_services": [
{
"item_identifier": "PROD01",
"item_name": "Product One",
"item_quantity": 1,
"item_gross_unit_sale_value": 1800,
"item_revenue_category": "Sales Revenue",
"item_net_unit_cost_value": null,
"item_net_unit_sale_value": 1500,
"item_unit_tax_value": 300,
"item_net_total_sale_value": 1500,
"item_gross_total_sale_value": 1800,
"item_tax_value": 300
}
],
"transaction_gross_value": 1800,
"transaction_gross_curr_value": 1800,
"transaction_net_value": 1500,
"transaction_cost_value": null,
"transaction_payments_value": null,
"transaction_payment_extras_value": null,
"transaction_tax_value": 300,
"party": {
"customer": {
"customer_identifier": "11",
"customer_name": "KP"
}
}
}
Thanks for your support, Matt
If I understand the question correctly you could use something like this
db.getCollection('yourTransactionsCollection').aggregate([
{
$sort: {
"transaction_reference": 1,
"object_creation_date": -1
}
},
{
$group: {
_id: "$transaction_reference",
"transaction_date": { $first: "$transaction_date" },
"object_creation_date": { $first: "$transaction_date" },
"transaction_sale_value": { $first: "$transaction_sale_value" }
}
}
])
which outputs a result like the following
{
"_id" : "SI-1",
"transaction_date" : "2016-06-16T00:00:00.201Z",
"object_creation_date" : "2016-06-16T00:00:00.201Z",
"transaction_sale_value" : null
}
Note that you can change the $sort
to just include the object_creation_date
but I included both transaction_reference
and object_creation_date
as I think it would make sense to create a composite index on both of them instead of just the creation date. Adjust that according to your indexes so that the $sort
will hit one.
In addition there was no document field transaction_sale_value
hence the null
for it in the result. Maybe you missed that or it is just not in your sample documents but I think you get the idea and can adjust it to your needs.
来源:https://stackoverflow.com/questions/38650002/query-for-latest-version-of-a-document-by-date-in-mongodb