Swift - Splitting strings with regex - ignoring search string

南楼画角 提交于 2019-12-05 21:25:46

You can define an extension like this:

extension String {
    func split(usingRegex pattern: String) -> [String] {
        //### Crashes when you pass invalid `pattern`
        let regex = try! NSRegularExpression(pattern: pattern)
        let matches = regex.matches(in: self, range: NSRange(0..<utf16.count))
        let ranges = [startIndex..<startIndex] + matches.map{Range($0.range, in: self)!} + [endIndex..<endIndex]
        return (0...matches.count).map {String(self[ranges[$0].upperBound..<ranges[$0+1].lowerBound])}
    }
}

let str = "hi|thisZshouldZYbe|separated"
let separator = "\\||ZY?"
let result = str.split(usingRegex: separator)
print(result) //->["hi", "this", "should", "be", "separated"]

The above code does not work as you expect when you use "\\||Z|ZY", but I think you can modify your pattern to fit into this extension.

My suggestion is to create an UUID string as separator, then replace the occurrences of the regex pattern with this UUID string and split the string.

let string = "hi|thisZshouldZYbe|separated"
let uuid = UUID().uuidString
let result = string.replacingOccurrences(of: "\\||ZY?", with: uuid, options: .regularExpression).components(separatedBy: uuid)

Your pattern works only in another order of the OR parts ("\\||ZY|Z")

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