Regarding to this: polynomial equation parameters
where I get 3 parameters for a squared function y = a*x² + b*x + c
now I want only to get the first parameter for a squared function which describes my function y = a*x²
. With other words: I want to set b=c=0
and get the adapted parameter for a
. In case I understand it right, polyfit isn't able to do this.
This can be done by numpy.linalg.lstsq. To explain how to use it, it is maybe easiest to show how you would do a standard 2nd order polyfit 'by hand'. Assuming you have your measurement vectors x
and y
, you first construct a so-called design matrix M
like so:
M = np.column_stack((x**2, x, np.ones_like(x)))
after which you can obtain the usual coefficients as the least-square solution to the equation M * k = y
using lstsq
like this:
k, _, _, _ = np.linalg.lstsq(M, y)
where k
is the column vector [a, b, c]
with the usual coefficients. Note that lstsq
returns some other parameters, which you can ignore. This is a very powerful trick, which allows you to fit y
to any linear combination of the columns you put into your design matrix. It can be used e.g. for 2D fits of the type z = a * x + b * y
(see e.g. this example, where I used the same trick in Matlab), or polyfits with missing coefficients like in your problem.
In your case, the design matrix is simply a single column containing x**2
. Quick example:
import numpy as np
import matplotlib.pylab as plt
# generate some noisy data
x = np.arange(1000)
y = 0.0001234 * x**2 + 3*np.random.randn(len(x))
# do fit
M = np.column_stack((x**2,)) # construct design matrix
k, _, _, _ = np.linalg.lstsq(M, y) # least-square fit of M * k = y
# quick plot
plt.plot(x, y, '.', x, k*x**2, 'r', linewidth=3)
plt.legend(('measurement', 'fit'), loc=2)
plt.title('best fit: y = {:.8f} * x**2'.format(k[0]))
plt.show()
Result:
The coefficients are get to minimize the squared error, you don't assign them. However, you can set some of the coefficients to zero if they are too much insignificant. E.g., I have a list of points on curve y = 33*x²
:
In [51]: x=np.arange(20)
In [52]: y=33*x**2 #y = 33*x²
In [53]: coeffs=np.polyfit(x, y, 2)
In [54]: coeffs
Out[54]: array([ 3.30000000e+01, 8.99625199e-14, -7.62430619e-13])
In [55]: epsilon=np.finfo(np.float32).eps
In [56]: coeffs[np.abs(coeffs)<epsilon]=0
In [57]: coeffs
Out[57]: array([ 33., 0., 0.])
来源:https://stackoverflow.com/questions/22126229/numpy-polyfit-with-adapted-parameters