insert values from a drop down list to database table

问题

I am new to PHP. When i am trying to insert the value from drop down list to database table showing some errors

the code

<html>
<head>
<title>OPTION</title>
</head>
<body>
<form action="option.php" method="get">
Name :<select name="name">
<option value="name1">name1</option>
<option value="name2">name2</option>
<option value="name3">name3</option>
<option value="name4">name4</option>
</select><br>
<input type="submit" name="submit" value="Insert">
</form>
</body>
</html>
<?php
if(isset($_GET['submit']))
{
    $name=$_GET['name'];
    $c=mysql_connect("localhost","root","");
    mysql_select_db("test");
    $ins=mysql_query("insert into option (name) values ('$name')",$c);
    if($ins)
    {
        echo "<br>".$name."inserted";
    }
    else
    {
        echo mysql_error();
    }
}
?>

when i am trying out put showing this error

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'option (name) values ('name3')' at line 1

Thank you..,

回答1:

you have to change the name of your table (option). Option is a mysql keyword and so it will cause syntax error while executing queries with php.

Change the table name to option_test or something and make appropriate changes in your php code too. Then it will work.

Also start using mysqli_ or PDO since mysql_ has been deprecated from PHP5 onwards.

回答2:

Try this code, I changed the name of select to names and

use backticks around table name

    <form action="option.php" method="GET">
    Name :<select name="names">
    <option value="name1">name1</option>
    <option value="name2">name2</option>
    <option value="name3">name3</option>
    <option value="name4">name4</option>
    </select><br>
    <input type="submit" name="submit" value="Insert">
    </form>

    <?php
    if(isset($_GET['names']))
    {
        $name=$_GET['names'];
        $c=mysql_connect("localhost","root","");
        mysql_select_db("test");
        $ins=mysql_query("INSERT INTO `option` 
                          (name)
                          VALUES ('$name')",$c) or die(mysql_error());
        if($ins)
        {
            echo "<br>".$name."inserted";
        }

    }

?>

回答3:

Html Code Is:

<select name="a">
    <option value="val1">value1<option>
    <option value="val2">value2<option>
    <option value="val3">value3<option>
</select>

PHP Code Is:

<?php
    $a=$_POST[a];
?>

The above php code will help you to fetch data from the selected option into php variable $a. From there on ou can insert your data into the query simply as you inserted before.

回答4:

in your code mysql_query("insert into option (name) values ('$name')",$c); here is no need to add connection variable to that function.
you can just write mysql_query("insert into option (name) values ('$name')")or die(mysql_error()); reason for calling function mysql_error() is that you came to know what type of error is coming..
and another thing is you should change the name of your table from option to option1 or anything else...then it will work fine..no worry...:)

来源：https://stackoverflow.com/questions/24029212/insert-values-from-a-drop-down-list-to-database-table

标签

php

html

mysql

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