How do you get an unsigned long out of a string?

问题

What's the safest and best way to retrieve an unsigned long from a string in C++?

I know of a number of possible methods.

First, converting a signed long taken from atol.

char *myStr; // Initalized to some value somehow.
unsigned long n = ((unsigned)atol(myStr));

The obvious problem with this is, what happens when the value stored in myStr is larger than a signed long can contain? What does atol retrieve?

The next possibility is to use strtoul.

char *myStr; // Initalized to some value somehow.
unsigned long n = strtoul(myStr, 0, 10);

However, this is a little over complicated for my needs. I'd like a simple function, string in, unsigned long base 10 out. Also, the error handling leaves much to be desired.

The final possibility I have found is to use sscanf.

char *myStr; // Initalized to some value somehow.
unsigned long n = 0;
if(sscanf(myStr, "%lu", n) != 1) {
    //do some error handling
}

Again, error handling leaves much to be desired, and a little more complicated than I'd like.

The remaining obvious option is to write my own either a wrapper around one of the previous possibilities or some thing which cycles through the string and manually converts each digit until it reaches ULONG_MAX.

My question is, what are the other options that my google-fu has failed to find? Any thing in the C++ std library that will cleanly convert a string to an unsigned long and throw exceptions on failure?

My apologies if this is a dupe, but I couldn't find any questions that exactly matched mine.

回答1:

One way to do it:

stringstream(str) >> ulongVariable;

回答2:

You can use strtoul with no problem. The function returns an unsigned long. If convertion can not be performed the function return 0. If the correct long value is out of range the function return ULONG_MAX and the errno global variable is set to ERANGE.

回答3:

template <class T>
T strToNum(const std::string &inputString,
           std::ios_base &(*f)(std::ios_base&) = std::dec)
{
    T t;
    std::istringstream stringStream(inputString);

    if ((stringStream >> f >> t).fail())
    {
        throw runtime_error("Invalid conversion");
    }
    return t;
}


// Example usage
unsigned long ulongValue = strToNum<unsigned long>(strValue);
int intValue             = strToNum<int>(strValue);

int intValueFromHex      = strToNum<int>(strHexValue,std::hex);
unsigned long ulOctValue = strToNum<unsigned long>(strOctVal, std::oct);

回答4:

If you can use the boost libraries (www.boost.org) look at the conversion library - it's a header only include

#include "boost/lexical_cast.hpp"

then all you need to do is

unsigned long ul = boost::lexical_cast<unsigned long>(str);

回答5:

Jeffrey Stedfast has a beautiful post about writing int parser routines for Mono (in C).
It generates code that uses uses native types (you need 32 bit to parse 32 bit) and error codes for overflow.

回答6:

Use "atol" in-built std function

For example std::string input = "1024";

std::atol(input.c_str());

Atol expect parameter to be of type c string, so c_str() does it that for you.

回答7:

Robust way will be write a static function and use it

bool str2Ulong(const string& str,unsigned long & arValue)
{
   char *tempptr=NULL;
   arValue=strtoul(str,tempptr,10);

   return ! (arValue==0 && tempptr==str.c_str());

}

来源：https://stackoverflow.com/questions/1484140/how-do-you-get-an-unsigned-long-out-of-a-string

标签

c++

long-integer

unsigned

string-parsing

string-conversion