Variadic macros with 0 arguments in C99

问题

I have some debugging code that looks like the following:

#define STRINGIFY(x) #x
#define TOSTRING(x) STRINGIFY(x)
#define AT __FILE__ ":" TOSTRING(__LINE__)
void __my_error(const char*loc, const char *fmt, ...);
#define my_error(fmt, ...) __my_error(AT, fmt, ##__VA_ARGS__)

The last macro is used so I can insert the location into the debug output as to where the error occurred. However, when I call the function like this:

my_error("Uh oh!");

I would like my code to be C99, so I find when this compiles, I get the following error:

error: ISO C99 requires rest arguments to be used

I know I can solve this by changing the call to

my_error("Uh oh!", NULL);

But is there any way to make this look less ugly? Thanks!

回答1:

I see two solutions to this problem. (Three if you count 'stick with gcc').

Extra special case macro

Add a new macro for when you want to print a fixed string.

#define my_errorf(str) my_error(str, NULL)

Pro: Minimum amount of extra code.
Con: It's easy to use the wrong macro (but at least you notice this at compile time).

Put fmt inside the '...'

Vararg macro's can have only __VA_ARGS__ as parameter (unlike vararg functions). So you can put the fmt argument inside the __VA_ARGS__ and change your function.

void __my_error(const char *loc, ...);
#define my_error(...) __my_error(AT, __VA_ARGS__)

Pro: One syntax/macro for all error messages.
Con: Requires rewriting of your __my_error function, which might not be possible.

来源：https://stackoverflow.com/questions/3576396/variadic-macros-with-0-arguments-in-c99