I'm using a map with a layer (from the example):
var lonLat = new OpenLayers.LonLat(40.4088576, -86.8576718)
.transform(
new OpenLayers.Projection("EPSG:4326"), // transform from WGS 1984
map.getProjectionObject() // to Spherical Mercator Projection
);
on moveend i'm get center coordinates:
map.getCenter();
map.getZoom();
and zoom level: 4925535.4503328, -9668990.0134335, 12
Using algorithm from documentation
public PointF TileToWorldPos(double tile_x, double tile_y, int zoom)
{
PointF p = new Point();
double n = Math.PI - ((2.0 * Math.PI * tile_y) / Math.Pow(2.0, zoom));
p.X = (float)((tile_x / Math.Pow(2.0, zoom) * 360.0) - 180.0);
p.Y = (float)(180.0 / Math.PI * Math.Atan(Math.Sinh(n)));
return p;
}
i get Y ~ 90, and X ~ 432662
but i need coordinates in bounds: -180..180
something like: 40.4088576, -86.8576718
what is wrong?
Why not just get OpenLayers to project it back for you? So if you want the centre point as WGS84 then just do:
var center = map.getCenter().transform(map.getProjectionObject(),
new OpenLayers.Projection("EPSG:4326"));
I think you'll find that will do what you want anyway, at least if I've understood the question right...
By the way, EPSG:4326 is the natural WGS84 lat/lon values that you seem to be looking for - the large numbers are the projected coordinates in spherical mercator, which is EPSG:900913.
来源:https://stackoverflow.com/questions/7569179/osm-convert-ties-from-projected-coordinates-in-spherical-mercator-epsg900913