Echo all months with days calendar

问题

I am using the code below to echo the current month. How can i enhance it so that is shows all the months with the names and days and dates..

Code:

 <?php
$today    = getdate();
$firstDay = getdate(mktime(0,0,0,$today['mon'],1,$today['year']));
$lastDay  = getdate(mktime(0,0,0,$today['mon']+1,0,$today['year']));


?>

<?php

echo '<table>';
echo '  <tr><th colspan="7">'.$today['month']." - ".$today['year']."</th></tr>";
echo '<tr class="days">';
echo '  <td>Mo</td><td>Tu</td><td>We</td><td>Th</td>';
echo '  <td>Fr</td><td>Sa</td><td>Su</td></tr>';
?> 

<?php
echo '<tr>';
for($i=1;$i<$firstDay['wday'];$i++){
    echo '<td>&nbsp;</td>';
}
$actday = 0;
for($i=$firstDay['wday'];$i<=7;$i++){
    $actday++;
    echo "<td>$actday</td>";
}
echo '</tr>';
?> 

<?php
$fullWeeks = floor(($lastDay['mday']-$actday)/7);

for ($i=0;$i<$fullWeeks;$i++){
    echo '<tr>';
    for ($j=0;$j<7;$j++){
        $actday++;
        echo "<td>$actday</td>";
    }
    echo '</tr>';
    }
    ?> 

    <?php
    if ($actday < $lastDay['mday']){
    echo '<tr>';

    for ($i=0; $i<7;$i++){
        $actday++;
        if ($actday <= $lastDay['mday']){
            echo "<td>$actday</td>";
        }
        else {
            echo '<td>&nbsp;</td>';
        }
    }

    echo '</tr>';
}
?>

回答1:

Try this:

function getDates($year)
{
    $dates = array();

    date("L", mktime(0,0,0, 7,7, $year)) ? $days = 366 : $days = 365;
    for($i = 1; $i <= $days; $i++){
        $month = date('m', mktime(0,0,0,1,$i,$year));
        $wk = date('W', mktime(0,0,0,1,$i,$year));
        $wkDay = date('D', mktime(0,0,0,1,$i,$year));
        $day = date('d', mktime(0,0,0,1,$i,$year));

        $dates[$month][$wk][$wkDay] = $day;
    } 

    return $dates;   
}

it will return an array of months->weeks->day->weekday of the year you pass to the function. Hopefully it should be easy to traverse through the array to print everything out. Am sure there are a lot of tweaks you can make to that but its a start.

I would also try and stay away from printing out html using echo, for example instead of;

echo '<tr>';
for($i=1;$i<$firstDay['wday'];$i++){
    echo '<td>&nbsp;</td>';
}

do;

<tr>;
<?php for($i=1;$i<$firstDay['wday'];$i++){ ?>
    <td><?php echo $var; ?></td>
<?php } ?>

It kind of makes the code more readable I think.

EDIT: Just thought I should include an example of a use case as well, as below:

<?php $dates = getDates(2011); 

$weekdays = array('Mon', 'Tue', 'Wed', 'Thu', 'Fri', 'Sat', 'Sun'); ?>
<?php foreach($dates as $month => $weeks) { ?>
<table>
    <tr>
        <th><?php echo implode('</th><th>', $weekdays); ?></th>
    </tr>
    <?php foreach($weeks as $week => $days){ ?>
    <tr>
        <?php foreach($weekdays as $day){ ?>
        <td>
            <?php echo isset($days[$day]) ? $days[$day] : '&nbsp'; ?>
        </td>               
        <?php } ?>
    </tr>
    <?php } ?>
</table>
<?php } ?>

Which gives you the output:

回答2:

You can use this function to convert entire year into array

  function year2array($year) {
    $res = $year >= 1970;
    if ($res) {
      // this line gets and sets same timezone, don't ask why :)
      date_default_timezone_set(date_default_timezone_get());

      $dt = strtotime("-1 day", strtotime("$year-01-01 00:00:00"));
      $res = array();
      $week = array_fill(1, 7, false);
      $last_month = 1;
      $w = 1;
      do {
        $dt = strtotime('+1 day', $dt);
        $dta = getdate($dt);
        $wday = $dta['wday'] == 0 ? 7 : $dta['wday'];
        if (($dta['mon'] != $last_month) || ($wday == 1)) {
          if ($week[1] || $week[7]) $res[$last_month][] = $week;
          $week = array_fill(1, 7, false);
          $last_month = $dta['mon'];
          }
        $week[$wday] = $dta['mday'];
        }
      while ($dta['year'] == $year);
      }
    return $res;
    }

Call it like

print_r(year2array(2011));

You'll see this in source (months->weeks->days):

So, now it's easy to create month table for every month you need using something like this

  function month2table($month, $calendar_array) {
    $ca = 'align="center"';
    $res = "<table cellpadding=\"2\" cellspacing=\"1\" style=\"border:solid 1px #000000;font-family:tahoma;font-size:12px;background-color:#ababab\"><tr><td $ca>Mo</td><td $ca>Tu</td><td $ca>We</td><td $ca>Th</td><td $ca>Fr</td><td $ca>Sa</td><td $ca>Su</td></tr>";
    foreach ($calendar_array[$month] as $month=>$week) {
      $res .= '<tr>';
      foreach ($week as $day) {
        $res .= '<td align="right" width="20" bgcolor="#ffffff">' . ($day ? $day : '&nbsp;') . '</td>';
        }
      $res .= '</tr>';
      }
    $res .= '</table>';
    return $res;
    }

Use these functions like

  $calarr = year2array(2011);
  echo month2table(1, $calarr); // January
  echo month2table(2, $calarr); // February
  ...
  echo month2table(12, $calarr); // December

..or put months in for loop.

So... e.g. for January 2011 in your browser you'll see this

Hope this helps.

回答3:

$daysArr = array('Mon','Tue','Wed','Thu','Fri','Sat','Sun');
$monthtotdays= cal_days_in_month(CAL_GREGORIAN,date('m'),date("Y"));
$currdays=jddayofweek (cal_to_jd(CAL_GREGORIAN, date('m'),1, date("Y")) , 2 );
$currdaysval = 0;
echo "<table border=1px>";
echo "<tr>";
for($d=0;$d<=6;$d++){
echo "<td>". $daysArr[$d]."</td>";
if($daysArr[$d]==$currdays)  $currdaysval = $d;
}

echo "</tr>";
echo "<tr>";
if($currdaysval > 0 ){
echo '<td colspan="'.$currdaysval.'">&nbsp;</td>';
}
for($i=1;$i<=$monthtotdays;$i++){
echo "<td>".$i."</td>";
if(($i+$currdaysval )%7 <= 0 ){
echo "</tr><tr>";
}
}
echo "</tr></table>"

回答4:

The best answer has an inaccuracy! You should add a condition if year is leap-year BEFORE a cycle, otherwise you will have problems with output of first days of first month see screenshot.

The necessary condition: date("L", mktime(0,0,0, 7,7, $year)) ? $days = 366 : $days = 365; (if year is leap-year then counter of cycle = 366 else 365)

回答5:

Wrap your current code within a function then pass an argument to it with your desired date.

来源：https://stackoverflow.com/questions/5536041/echo-all-months-with-days-calendar

标签

php

calendar

getdate