问题
<?php
$str = "word <a href=\"word\">word</word>word word";
$str = preg_replace("/word(?!([^<]+)?>)/i","repl",$str);
echo $str;
# repl <word word="word">repl</word>
?>
source: http://pureform.wordpress.com/2008/01/04/matching-a-word-characters-outside-of-html-tags/
Unfortunality my project needs a semantic libs avaliable only for Java...
// Thanks Celso
回答1:
Use the String.replaceAll() method:
class Test {
public static void main(String[] args) {
String str = "word <a href=\"word\">word</word>word word";
str = str.replaceAll("word(?!([^<]+)?>)", "repl");
System.out.println(str);
}
}
Hope this helps.
回答2:
To translate that regex for use in Java, all you have to do is get rid of the /
delimiters and change the trailing i
to an inline modifier, (?i)
. But it's not a very good regex; I would use this instead:
(?i)word(?![^<>]++>)
According to RegexBuddy's Debug feature, when it tries to match the word
in <a href="word">
, the original regex requires 23 steps to reject it, while this one takes only seven steps. The actual Java code is
str = str.replaceAll("(?i)word(?![^<>]++>)", "repl");
回答3:
Before providing a further answer, are you trying to parse an html document? If so, don't use regexes, use an html parser.
来源:https://stackoverflow.com/questions/3304925/what-is-the-java-equivalent-to-this-preg-replace