问题
In python, it's fairly straightforward to reference a function:
>>> def foo():
... print "foo called"
... return 1
...
>>> x = foo
>>> foo()
foo called
1
>>> x()
foo called
1
>>> x
<function foo at 0x1004ba5f0>
>>> foo
<function foo at 0x1004ba5f0>
However, it seems to be different in Ruby since a naked foo
actually calls foo:
ruby-1.9.2-p0 > def foo
ruby-1.9.2-p0 ?> print "foo called"
ruby-1.9.2-p0 ?> 1
ruby-1.9.2-p0 ?> end
=> nil
ruby-1.9.2-p0 > x = foo
foo called => 1
ruby-1.9.2-p0 > foo
foo called => 1
ruby-1.9.2-p0 > x
=> 1
How do I actually assign the function foo to x and then call it? Or is there a more idiomatic way to do this?
回答1:
Ruby doesn't have functions. It only has methods (which aren't first-class) and Proc
s which are first-class, but are not associated with any object.
So, this is a method:
def foo(bar) puts bar end
foo('Hello')
# Hello
Oh, and, yes, this is a real method, not a top-level function or procedure or something. Methods defined at the top-level end up as private(!) instance methods in the Object
class:
Object.private_instance_methods(false) # => [:foo]
This is a Proc
:
foo = -> bar { puts bar }
foo.('Hello')
# Hello
Notice that Proc
s are called differently from methods:
foo('Hello') # method
foo.('Hello') # Proc
The foo.(bar)
syntax is just syntactic sugar for foo.call(bar)
(which for Proc
s and Method
s is also aliased to foo[bar]
). Implementing a call
method on your object and then calling it with .()
is the closest thing you will get to Python's __call__
ables.
Note that an important distinction between Ruby Proc
s and Python lambdas is that there are no restrictions: in Python, a lambda can only contain a single statement, but Ruby doesn't have the distinction between statements and expressions (everything is an expression), and so this limitation simply doesn't exist, therefore in a lot of cases where you need to pass a named function as an argument in Python because you cannot express the logic in a single statement, you would in Ruby simply pass a Proc
or a block instead, so that the problem of the ugly syntax for referencing methods doesn't even arise.
You can wrap a method in a Method
object (which essentially duck-types Proc
) by calling the Object#method
method on an object (which will give you a Method
whose self
is bound to that particular object):
foo_bound = method(:foo)
foo_bound.('Hello')
# Hello
You can also use one of the methods in the Module#instance_method
family to get an UnboundMethod
from a module (or class, obviously, since a class is-a module), which you can then UnboundMethod#bind
to a particular object and call. (I think Python has the same concepts, albeit with a different implementation: an unbound method simply takes the self argument explicitly, just like the way it is declared.)
foo_unbound = Object.instance_method(:foo) # this is an UnboundMethod
foo_unbound.('Hello')
# NoMethodError: undefined method `call' for #<UnboundMethod: Object#foo>
foo_rebound = foo_unbound.bind(self) # this is a Method
foo_rebound.('Hello')
# Hello
Note that you can only bind an UnboundMethod
to an object which is an instance of the module you took the method from. You cannot use UnboundMethods
to "transplant" behavior between unrelated modules:
bar = module Foo; def bar; puts 'Bye' end; self end.instance_method(:bar)
module Foo; def bar; puts 'Hello' end end
obj = Object.new
bar.bind(obj)
# TypeError: bind argument must be an instance of Foo
obj.extend(Foo)
bar.bind(obj).()
# Bye
obj.bar
# Hello
Note, however, that both the Method
and the UnboundMethod
are wrappers around the method, not the method itself. Methods are not objects in Ruby. (Contrary to what I have written in other answers, BTW. I really need to go back and fix those.) You can wrap them in objects, but they aren't objects, and you can see that because you essentially get all the same problems you always get with wrappers: identity and state. If you call method
multiple times for the same method, you will get a different Method
object every time. If you try to store some state on that Method
object (such as Python-style __doc__
strings, for example), that state will be private to that particular instance, and if you try to retrieve your docstring again via method
, you will find that it is gone.
There is also syntactic sugar in the form of the method reference operator .:
:
bound_method = obj.:foo
Which is identical to
bound_method = obj.method(:foo)
回答2:
You can use the method
instance method inherited from Object to retrieve a Method object, which essentially is a Proc object which you can invoke call
on.
In the console, you'd do this:
fooMethod = self.method(:foo) #fooMethod is a Method object
fooMethod.call #invokes fooMethod
回答3:
Ruby supports proc and lambda which in other languages might be called anonymous functions or closures, depending on how they are used. They might be closer to what you are looking for.
回答4:
The (main) difference between functions and methods as copied from https://stackoverflow.com/a/26620095/226255
Functions are defined outside of classes, while methods are defined inside of and part of classes.
Ruby does not have functions and your def foo
ends up being a method for the Object
class.
If you insist on defining foo
like you're doing above, you can extract its "functionality" by doing this:
def foo(a,b)
a+b
end
x = method(:foo).to_proc
x.call(1,2)
=> 3
Explanation:
> method(:foo) # this is Object.method(:foo), returns a Method object bound to
# object of type 'Class(Object)'
=> #<Method: Class(Object)#foo>
method(:foo).to_proc
# a Proc that can be called without the original object the method was bound to
=> #<Proc:0x007f97845f35e8 (lambda)>
Important note:
to_proc
"copies" the method's object's associated instance variables if any. Consider this:
class Person
def initialize(name)
@name = name
end
def greet
puts "hello #{@name}"
end
end
greet = Person.new('Abdo').method(:greet)
# note that Person.method(:greet) returns an UnboundMethod and cannot be called
# unless you bind it to an object
> greet.call
hello Abdo
=> nil
Conceptually, if you want a "function" that would work on a certain type of objects, it should be a method and you should organize your code as such. If you only need your "function" in a certain context and wish to pass it around, use lambdas:
greet = lambda { |person| "hello #{person}" }
yell_at = lambda { |person| "HELLO #{person.upcase}" }
def do_to_person(person, m)
m.call(person)
end
do_to_person('Abdo', greet)
来源:https://stackoverflow.com/questions/4294485/how-do-i-reference-a-function-in-ruby