问题
I'm using will_paginate for pagination, which has been working well so far, except for this one thing.
If I try to paginate a scope, for instance
class User < ActiveRecord::Base
named_scope :scope, lambda { etc }
end
User.scope.paginate({:page => params[:page], :per_page => 10})
That will tell me paginate is an undefined method. I'd rather not have to use a second solution for only this scope, is there something I can do here?
回答1:
Lowgain, klew's version should work out of the box. In your version you should write:
User.scope.paginate :page => params[:page], :per_page => 10
I prefer another approach to pagination. It allows to make controller more clean and encapsulates pagination at model level, for e.g.:
class Property < ActiveRecord::Base
named_scope :all_properties, lambda {{ :order => "name asc" }}
def self.admin_properties(page = 1)
self.all_properties.paginate(:page => page, :per_page => Settings.admin.per_page)
end
end
And in a controller pretty clear code:
class Admin::PropertiesController < Admin::AdminController
def index
@properties = Property.admin_properties(params[:page])
end
end
p.s: Settings.admin.per_page - this is Searchlogic settings.
回答2:
I have a named_scope
defined like this:
named_scope :look_for, lambda { |search| bla;bla;bla }
I call it:
Person.look_for(params[:search]).paginate :page => params[:page]
And it works. Maybe you need some parameter to your scope?
回答3:
Kind of a weird solution, but
User.scope.find(:all).paginate :page => params[:page], :per_page => 10
works?
回答4:
Lowgain, it doesn't sound like you are, but just to make sure -- you aren't actually doing tests with a named_scope named scope right? Because scope is an existing method and using that as your scope name causes an error (and an infinite loop).
EDIT:
Does your named_scope happen to include a :limit clause? I just started having a similar problem. I have a model Response which belongs_to User, with a named scope something like this:
named_scope :top, lambda { |limit| {
:limit => limit,
:order => 'total_score DESC' }}
And I am seeing results in the console such as this:
?> u = User.find 1
?> u.responses.length
=> 9
?> u.responses.paginate(:page => 1, :per_page => 5).length
=> 5
?> u.responses.top(3).length
=> 3
?> u.responses.top(3).paginate(:page => 1, :per_page => 5).length
=> 5
Yikes! How can my top 3 paginate to produce more than 3 rows? Per your example I tried your find(:all) trick with similar results:
?> u.responses.top(3).find(:all).paginate(:page => 1, :per_page => 5).length
=> 3
This looks like a bug in named_scope, because I can take will_paginate out of the picture and get similar mayhem to occur:
?> u.responses.top(3).length
=> 3
?> u.responses.top(3).size
=> 9 <-- .size produces wrong answer
?> r = u.responses.top(3)
?> r.size
=> 3 <-- correct when result assigned to var
So far, this only appears to happen when I am using MySQL. I think I read another post on StackOverflow where someone had a similar problem using .size with AR results and MySQL, and the solution was to always use .length on their AR results. I have tried modifying will_paginate to replace all instances of .size with .length, but alas it was not that simple, but I suspect that this or a similar issue is somehow affecting will_paginate.
For the time being, I am using your find(:all) trick to hack around this.
来源:https://stackoverflow.com/questions/2792119/will-paginate-with-named-scopes