问题
I am using Swift 4 and trying to parse some JSON data which apparently in some cases can have different type values for the same key, e.g.:
{
"type": 0.0
}
and
{
"type": "12.44591406"
}
I am actually stuck with defining my struct
because I cannot figure out how to handle this case because
struct ItemRaw: Codable {
let parentType: String
enum CodingKeys: String, CodingKey {
case parentType = "type"
}
}
throws "Expected to decode String but found a number instead."
, and naturally,
struct ItemRaw: Codable {
let parentType: Float
enum CodingKeys: String, CodingKey {
case parentType = "type"
}
}
throws "Expected to decode Float but found a string/data instead."
accordingly.
How can I handle this (and similar) cases when defining my struct
?
回答1:
I ran into the same issue when trying to decode/encode the "edited" field on a Reddit Listing JSON response. I created a struct that represents the dynamic type that could exist for the given key. The key can have either a boolean or an integer.
{ "edited": false }
{ "edited": 123456 }
If you only need to be able to decode, just implement init(from:). If you need to go both ways, you will need to implement encode(to:) function.
struct Edited: Codable {
let isEdited: Bool
let editedTime: Int
// Where we determine what type the value is
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
// Check for a boolean
do {
isEdited = try container.decode(Bool.self)
editedTime = 0
} catch {
// Check for an integer
editedTime = try container.decode(Int.self)
isEdited = true
}
}
// We need to go back to a dynamic type, so based on the data we have stored, encode to the proper type
func encode(to encoder: Encoder) throws {
var container = encoder.singleValueContainer()
try isEdited ? container.encode(editedTime) : container.encode(false)
}
}
Inside my Codable class, I then use my struct.
struct Listing: Codable {
let edited: Edited
}
Edit: A more specific solution for your scenario
I recommend using the CodingKey protocol and an enum to store all the properties when decoding. When you create something that conforms to Codable the compiler will create a private enum CodingKeys for you. This lets you decide on what to do based on the JSON Object property key.
Just for example, this is the JSON I am decoding:
{"type": "1.234"}
{"type": 1.234}
If you want to cast from a String to a Double because you only want the double value, just decode the string and then create a double from it. (This is what Itai Ferber is doing, you would then have to decode all properties as well using try decoder.decode(type:forKey:))
struct JSONObjectCasted: Codable {
let type: Double?
init(from decoder: Decoder) throws {
// Decode all fields and store them
let container = try decoder.container(keyedBy: CodingKeys.self) // The compiler creates coding keys for each property, so as long as the keys are the same as the property names, we don't need to define our own enum.
// First check for a Double
do {
type = try container.decode(Double.self, forKey: .type)
} catch {
// The check for a String and then cast it, this will throw if decoding fails
if let typeValue = Double(try container.decode(String.self, forKey: .type)) {
type = typeValue
} else {
// You may want to throw here if you don't want to default the value(in the case that it you can't have an optional).
type = nil
}
}
// Perform other decoding for other properties.
}
}
If you need to store the type along with the value, you can use an enum that conforms to Codable instead of the struct. You could then just use a switch statement with the "type" property of JSONObjectCustomEnum and perform actions based upon the case.
struct JSONObjectCustomEnum: Codable {
let type: DynamicJSONProperty
}
// Where I can represent all the types that the JSON property can be.
enum DynamicJSONProperty: Codable {
case double(Double)
case string(String)
init(from decoder: Decoder) throws {
let container = try decoder.singleValueContainer()
// Decode the double
do {
let doubleVal = try container.decode(Double.self)
self = .double(doubleVal)
} catch DecodingError.typeMismatch {
// Decode the string
let stringVal = try container.decode(String.self)
self = .string(stringVal)
}
}
func encode(to encoder: Encoder) throws {
var container = encoder.singleValueContainer()
switch self {
case .double(let value):
try container.encode(value)
case .string(let value):
try container.encode(value)
}
}
}
回答2:
One simple solution is to provide an implementation of init(from:)
which attempts to decode the value as a String
, and if that fails because the type is wrong, attempt to decode as a Double
:
public init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
do {
self.parentType = try container.decode(String.self, forKey: .parentType)
} catch DecodingError.typeMismatch {
let value = try container.decode(Double.self, forKey: .parentType)
self.parentType = "\(value)"
}
}
回答3:
I had to decode PHP/MySQL/PDO
double value that is given as an String, for this use-case I had to extend the KeyedDecodingContainer
, like so:
extension KeyedDecodingContainer {
func decode(forKey key: KeyedDecodingContainer.Key) throws -> Double {
do {
let str = try self.decode(String.self, forKey: key)
if let dbl = Double(str) {
return dbl
}
} catch DecodingError.typeMismatch {
return try self.decode(Double.self, forKey: key)
}
let context = DecodingError.Context(codingPath: self.codingPath,
debugDescription: "Wrong Money Value")
throw DecodingError.typeMismatch(Double.self, context)
}
}
Usage:
let data = """
{"value":"1.2"}
""".data(using: .utf8)!
struct Test: Decodable {
let value: Double
enum CodingKeys: String, CodingKey {
case value
}
init(from decoder: Decoder) throws {
self.value = try decoder.container(keyedBy: CodingKeys.self)
.decode(forKey: CodingKeys.value)
}
}
try JSONDecoder().decode(Test.self, from: data).value
来源:https://stackoverflow.com/questions/46759044/swift-structures-handling-multiple-types-for-a-single-property