Why can I use gets() in gcc -std=c11?

妖精的绣舞 提交于 2019-12-03 12:24:52

gcc is just the compiler, not the entire implementation.

On my system (Linux Mint 17.3, gcc 4.8.4, GNU libc 2.19), I get:

$ gcc -std=c11 -pedantic-errors -Wall -Wextra -c c.c
c.c: In function ‘main’:
c.c:5:3: error: implicit declaration of function ‘gets’ [-Wimplicit-function-declaration]
   (void) gets (NULL);
   ^

To correctly diagnose the error, the implementation needs to be conforming. That means both the compiler (which never provided gets in the first place) and the library.

You're using a library that still provides the gets function. Because of that the implementation as a whole (which consists of the compiler gcc, the library, and a few other pieces) does not conform to C11.

Bottom line: This is not a gcc issue, and there's not much that gcc can do about it. (Well, it could issue a special-case diagnostic for gets, but then it would have to determine that it's not a valid call to a user-defined function with the same name.)

The key line of your code is:

#include <stdio.h>

Did you update your system's C library and headers? They're also part of the C implementation, along with the compiler.

update this may not be an answer to the question, I try to make it informational.

I happened to find that gcc mentioned gets is not following C11 standard for some library issue glibc 2.16.

See gcc supporting status of C11: https://gcc.gnu.org/wiki/C11Status

But I cannot find the definition of "library issue" and current status for other versions of glibc.

So I tried on my machine ubuntu16.04 with gcc version 5.3.1 20160413, glibc version Ubuntu GLIBC 2.23 We can get enough warning on compile time, but it's still OK to execute the output object file for "Backwards compatibility".

warning: implicit declaration of function ‘gets’ [-Wimplicit-function-declaration]
warning: the `gets' function is dangerous and should not be used.
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