问题
template <unsigned int N> class myclass
{
public:
template <typename... Args> void mymethod(Args... args)
{
// Do interesting stuff
}
};
I want mymethod
to be called only with exactly N doubles. Is that possible? That is, say that I have:
myclass <3> x;
x.mymethod(3., 4., 5.); // This works
x.mymethod('q', 1., 7.); // This doesn't work
x.mymethod(1., 2.); // This doesn't work
How can I get this done?
回答1:
For the number of arguments constraint you can easily check if sizeof...(Args) == N
but for checking if all the arguments are doubles you need to build a recursive type trait that checks std::is_same
for each of the arguments.
template<typename...>
struct are_same : std::true_type
{};
template<typename T>
struct are_same<T> : std::true_type
{};
template<typename T, typename U, typename... Types>
struct are_same<T, U, Types...> :
std::integral_constant<bool, (std::is_same<T, U>::value && are_same<T, Types...>::value)>
{};
Notice are_same
is first declared and then specialized.
Then just implement the constraint in your method return type using std::enable_if
by taking advantage of SFINAE.
template <unsigned int N> class myclass
{
public:
template <typename... Args>
typename std::enable_if<(are_same<double, Args...>::value && sizeof...(Args) == N), void>::type
/* void */ mymethod(Args... args)
{
// Do interesting stuff
}
};
回答2:
Can try something like following :
#include <type_traits>
template<class T, class...>
struct all_same : std::true_type
{};
template<class T, class U, class... TT>
struct all_same<T, U, TT...>
: std::integral_constant<bool, std::is_same<T,U>{} && all_same<T, TT...>{}>
{};
template <unsigned int N> class myclass
{
public:
template <typename... Args>
typename std::enable_if<sizeof...(Args) == N, void >::type mymethod(Args... args)
{
static_assert(all_same<double, Args...>{},
"Not all args as Double");
}
};
<Demo>
来源:https://stackoverflow.com/questions/30179181/a-variadic-template-method-to-accept-a-given-number-of-doubles