问题
Given the following code snippet, how would you create a Jasmine spyOn
test to confirm that doSomething
gets called when you run MyFunction
?
function MyFunction() {
var foo = new MyCoolObject();
foo.doSomething();
};
Here's what my test looks like. Unfortunately, I get an error when the spyOn
call is evaluated:
describe("MyFunction", function () {
it("calls doSomething", function () {
spyOn(MyCoolObject, "doSomething");
MyFunction();
expect(MyCoolObject.doSomething).toHaveBeenCalled();
});
});
Jasmine doesn't appear to recognize the doSomething
method at that point. Any suggestions?
回答1:
When you call new MyCoolObject()
you invoke the MyCoolObject
function and get a new object with the related prototype. This means that when you spyOn(MyCoolObject, "doSomething")
you're not setting up a spy on the object returned by the new
call, but on a possible doSomething
function on the MyCoolObject
function itself.
You should be able to do something like:
it("calls doSomething", function() {
var originalConstructor = MyCoolObject,
spiedObj;
spyOn(window, 'MyCoolObject').and.callFake(function() {
spiedObj = new originalConstructor();
spyOn(spiedObj, 'doSomething');
return spiedObj;
});
MyFunction();
expect(spiedObj.doSomething).toHaveBeenCalled();
});
回答2:
Alternatively, as Gregg hinted, we could work with 'prototype'. That is, instead of spying on MyCoolObject directly, we can spy on MyCoolObject.prototype.
describe("MyFunction", function () {
it("calls doSomething", function () {
spyOn(MyCoolObject.prototype, "doSomething");
MyFunction();
expect(MyCoolObject.prototype.doSomething).toHaveBeenCalled();
});
});
来源:https://stackoverflow.com/questions/22291371/how-to-use-jasmine-spies-on-an-object-created-inside-another-method