Understanding the different behavior of thunks when GHCi let bindings are involved

我的梦境 提交于 2019-12-03 05:26:11

问题


I've been playing with some examples from Simon Marlow's book about parallel and concurrent programming in Haskell and stumbled across an interesting behavior that I don't really understand. This is really about me trying to understand some of the inner workings of GHC.

Let's say I do the following in the REPL:

λ» let x = 1 + 2 :: Int
λ» let z = (x,x)
λ» :sprint x
x = _
λ» :sprint z
z = (_,_)
λ» seq x ()
()
λ» :sprint z
z = (3,3)

Ok, this is pretty much what I expected except that z gets evaluated to WHNF already. Let's write a similar program and put it in a file:

module Thunk where

import Debug.Trace

x :: Int
x = trace "add" $ 1 + 2

z :: (Int,Int)
z = (x,x)

And fiddle around with it in GHCi:

λ» :sprint x
x = _
λ» :sprint z
z = _
λ» seq x ()
add
()
λ» :sprint z
z = _
λ» seq z ()
()
λ» z
(3,3)

So this behaves a little different: z is not evaluated to WHNF in advance. My question is:

Why is z evaluated to WHNF in the REPL when doing let z = (x,x) but not when loading the definition from a file. My suspicion is that it has something to do with pattern binding but I don't know where to look that up for clarification (maybe I'm just completely utterly wrong). I would have expected it to somehow behave like the example in the file.

Any pointers or a brief explanation why this happens?


回答1:


Because (,) is a constructor, the difference makes no difference to Haskell's semantics (:sprint gives access to internal thunk implementation details so doesn't count.) So this is a question of which optimizations and trade-offs GHC does when compiling (x,x) in different positions. Someone else may know the precise reason in these cases.



来源:https://stackoverflow.com/questions/24755672/understanding-the-different-behavior-of-thunks-when-ghci-let-bindings-are-involv

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!