Swift operator `subscript` []

自闭症网瘾萝莉.ら 提交于 2019-12-03 04:52:59

It looks like there are 2 questions here.

1. How can I enable subscripting on my own custom class?

To enable subscripting on your class Container you need to implement the subscript computed property like this.

class Container {
    private var list : [Any] = [] // I made this private

    subscript(index:Int) -> Any {
        get {
            return list[index]
        }
        set(newElm) {
            list.insert(newElm, atIndex: index)
        }
    }
}

Now you can use it this way.

var container = Container()
container[0] = "Star Trek"
container[1] = "Star Trek TNG"
container[2] = "Star Trek DS9"
container[3] = "Star Trek VOY"

container[1] // "Star Trek TNG"

2. Can I access one element of Container that supports subscripting writing something like data[1][2]?

If we use your example no, you cannot. Because data[1] returns something of type Any. And you cannot subscript Any.

But if you add a cast it becomes possible

var container = Container()
container[0] = ["Enterprise", "Defiant", "Voyager"]
(container[0] as! [String])[2] // > "Voyager"

A workaround is to leverage multiple parameters in subscript

So instead of data[1][2], you can say data[1, 2]. This will be handy in some cases

struct Container {
  subscript(a: Int, b: Int) -> String {
    print(a)
    print(b)
    return "possible"
  }
}

let data = Container()
data[1, 2]
class Container
{
    var list: [AnyObject] = ["hello" , "world"];
    subscript ( i : Int) -> AnyObject{
        get{
            return list[i]
        }
        set{
            list[i] = newValue
        }
    }
}

var c : Container = Container()
println(c[1])

c[1] = "lol"

println(c[1])

For more information about operator : http://nshipster.com/swift-operators/

It sounds like you are looking for subscripts. You can make subscripts for your own type like the following example:

class Container {
    var list = [["Hello", "World"], ["Foo", "Bar"]]

    subscript(index: Int) -> [String] {
        get {
            return list[index]
        }
        set {
            list.insert(newValue, atIndex: index)
        }
    }
}

The above example works with the double [ ] only because I know that we are going to return an Array. Here the Array contain Strings as an example, but you could of course swap in your own type

var container = Container()

container[0][0] = "Stack"
container[0][1] = "Overflow"

print(container[0][0]) // "Stack"
print(container[1][1]) // "Bar"
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