@csrf_exempt stopped working in Django 1.4

Question

I have the following code, that was working fine in Django 1.2.5:

from django.views.decorators.csrf import csrf_exempt

class ApiView(object):
    def __call__(self, request, *args, **kwargs):
        method = request.method.upper()
        return getattr(self, method)(request, *args, **kwargs)

@csrf_exempt
class MyView(ApiView):

    def POST(self):
       # (...)
       return HttpResponse(json.dumps(True), mimetype="text/javascript")

But when I upgraded to Django 1.4, I started to get a 403 forbidden, with a "CSRF verification failed" message.

Why is that @csrf_exempt decorator not working?

URL definition is:

from django.conf.urls.defaults import *
from django.views.decorators.csrf import csrf_exempt

import views

urlpatterns = patterns('',
   url(r'^myview/(?P<parameter_name>[A-Za-z0-9-_]+)/$',
       views.MyView(),
       name="myproject-myapp-myview",
       ),
)

Answer 1

According to the django docs:

To decorate every instance of a class-based view, you need to decorate the class definition itself. To do this you apply the decorator to the dispatch() method of the class.

So you'd need to do something like:

class MyView(ApiView):

    def POST(self):
       # (...)
       return HttpResponse(json.dumps(True), mimetype="text/javascript")

    @csrf_exempt
    def dispatch(self, *args, **kwargs):
        return super(MyView, self).dispatch(*args, **kwargs)

Answer 2

Just use csrf_exempt in the urls.py. ie::

urls.py

..other imports...
from django.views.decorators.csrf import csrf_exempt   
from myapp.views import MyView

urlpatterns = patterns('',
   url(r'^myview/(?P<parameter_name>[A-Za-z0-9-_]+)/$',
       csrf_exempt(MyView.as_view()), # use csrf_exempt here
       name="myproject-myapp-myview",
       ),
)

Answer 3

csrf_exempt has to decorate a function. In your urls you can decorate a that function, docs can be found here.

(r'^vote/', permission_required('polls.can_vote')(VoteView.as_view())),