Promise reject() causes “Uncaught (in promise)” warning

问题

Once a promise reject() callback is called, a warning message "Uncaught (in promise)" appears in the Chrome console. I can't wrap my head around the reason behind it, nor how to get rid of it.

var p = new Promise((resolve, reject) => {
  setTimeout(() => {
    var isItFulfilled = false
    isItFulfilled ? resolve('!Resolved') : reject('!Rejected')
  }, 1000)  
})

p.then(result => console.log(result))
p.catch(error => console.log(error))

Warning:

Edit:

I found out that if the onRejected handler is not explicitly provided to the .then(onResolved, onRejected) method, JS will automatically provide an implicit one. It looks like this: (err) => throw err. The auto generated handler will throw in its turn.

Reference:

If IsCallable(onRejected)` is false, then
     Let onRejected be "Thrower".

http://www.ecma-international.org/ecma-262/6.0/index.html#sec-performpromisethen

回答1:

This happens because you do not attach a catch handler to the promise returned by the first then method, which therefore is without handler for when the promise rejects. You do have one for the promise p in the last line, but not for the chained promise, returned by the then method, in the line before it.

As you correctly added in comments below, when a catch handler is not provided (or it's not a function), the default one will throw the error. Within a promise chain this error can be caught down the line with a catch method callback, but if none is there, the JavaScript engine will deal with the error like with any other uncaught error, and apply the default handler in such circumstances, which results in the output you see in the console.

To avoid this, chain the .catch method to the promise returned by the first then, like this:

p.then( result =>  console.log('Fulfilled'))
 .catch( error =>  console.log(error) );

回答2:

Even if you use Promises correctly: p.then(p1).catch(p2) you can still get an uncaught exception if your p2 function eventually throws an exception which you intend to catch using a mechanism like window.onerror. The reason is that the stack has already been unwound by the error handling done in the promise. To fix this, make sure that your error code (called by the reject function) does not throw an exception. It should simply return.

It would be nice if the error handling code could detect that the stack has already been unwound (so your error call doesn't have to have a flag for this case), and if anyone knows how to do this easily I will edit this answer to include that explanation.

来源：https://stackoverflow.com/questions/42460039/promise-reject-causes-uncaught-in-promise-warning