287. Find the Duplicate Number

Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one.

Example 1:

Input: [1,3,4,2,2]
Output: 2

Example 2:

Input: [3,1,3,4,2]
Output: 3

Note:

1. You must not modify the array (assume the array is read only).
2. You must use only constant, O(1) extra space.
3. Your runtime complexity should be less than O(n2).
4. There is only one duplicate number in the array, but it could be repeated more than once.

class Solution {
    public int findDuplicate(int[] nums) {
        Arrays.sort(nums);
        for (int i = 1; i < nums.length; i++) {
            if (nums[i] == nums[i-1]) {
                return nums[i];
            }
        }

        return -1;
    }
}

class Solution {
    public int findDuplicate(int[] nums) {
        Set<Integer> seen = new HashSet<Integer>();
        for (int num : nums) {
            if (seen.contains(num)) {
                return num;
            }
            seen.add(num);
        }

        return -1;
    }
}

class Solution {
    public int findDuplicate(int[] nums) {
        // Find the intersection point of the two runners.
        int tortoise = nums[0];
        int hare = nums[0];
        do {
            tortoise = nums[tortoise];
            hare = nums[nums[hare]];
        } while (tortoise != hare);

        // Find the "entrance" to the cycle.
        int ptr1 = nums[0];
        int ptr2 = tortoise;
        while (ptr1 != ptr2) {
            ptr1 = nums[ptr1];
            ptr2 = nums[ptr2];
        }

        return ptr1;
    }
}

有意思，龟兔赛跑，说是有点像https://leetcode.com/problems/linked-list-cycle-ii/

https://www.cnblogs.com/wentiliangkaihua/p/11392161.html

来源：https://www.cnblogs.com/wentiliangkaihua/p/11763396.html