java foreach skip first iteration

Question

Is there an elegant way to skip the first iteration in a Java5 foreach loop ?

Example pseudo-code:

for ( Car car : cars ) {     
   //skip if first, do work for rest
   .
   .
}

Answer 1

I wouldn't call it elegant, but perhaps better than using a "first" boolean:

for ( Car car : cars.subList( 1, cars.size() ) )
{
   .
   .
}

Other than that, probably no elegant method.  

Answer 2

With new Java 8 Stream API it actually becomes very elegant. Just use skip() method:

cars.stream().skip(1) // and then operations on remaining cars

Answer 3

Use Guava Iterables.skip().

Something like:

for ( Car car : Iterables.skip(cars, 1) ) {     
    // 1st element will be skipped
}

(Got this from the end of msandiford's answer and wanted to make it a standalone answer)

Answer 4

for (Car car : cars)
{
   if (car == cars[0]) continue;
   ...
}

Elegant enough for me.

Answer 5

SeanA's code has a tiny error: the second argument to sublist is treated as an exclusive index, so we can just write

for (Car car : cars.subList(1, cars.size()) {
   ...
}

(I don't seem to be able to comment on answers, hence the new answer. Do I need a certain reputation to do that?)  

Answer 6

I came a bit late to this, but you could use a helper method, something like:

public static <T> Iterable<T> skipFirst(final Iterable<T> c) {
    return new Iterable<T>() {
        @Override public Iterator<T> iterator() {
            Iterator<T> i = c.iterator();
            i.next();
            return i;
        }
    };
}

And use it something like this:

public static void main(String[] args) {
    Collection<Integer> c = Arrays.asList(1, 2, 3, 4, 5, 6, 7, 8, 9);
    for (Integer n : skipFirst(c)) {
        System.out.println(n);
    }
}

Generalizing to skip "n" is left as an exercise for the reader :)

---

EDIT: On closer inspection, I see that Guava has an Iterables.skip(...) here.

Answer 7

I'm not a java person but can you use :

for ( Car car : cars.tail() ) from java.util via Groovy JDK

Answer 8

Elegant? Not really. You'd need to check/set a boolean.

The for-each loop is for all practical purposes fancy syntax for using an iterator. You're better off just using an iterator and advancing before you start your loop.

Answer 9

Not so elegant but work with iterators

Iterator<XXXXX> rows = array.iterator();
if (rows.hasNext()){
    rows.next();
}
for (; rows.hasNext();) {
    XXXXX row = (XXXXX) rows.next();
}

Answer 10

This might not be elegant, but one could initialize an integer variable outside the for loop and increment it with every iteration within the loop. Your program would only execute if the counter is bigger than 0.

int counter = 0;
for ( Car car : cars ) {
    //skip if first, do work for rest
    if(counter>0){
        //do something
    }
    counter++;
}

Answer 11

You can use a counter. Though not so mature coding, still I find it the easiest way to skip the first element from a list.

    int ctr=0;
    for(Resource child:children) {
    if(ctr>0) { //this will skip the first element, i.e. when ctr=0
    //do your thing from the 2nd element onwards
    }
    ctr++;
    }