问题
I have to write a java code for the 'sieve of eratosthenes' algorithm to print out primes up to a given max value on the console but I'm not allowed to use arrays. Our professor told us it is possible to do only with the help of loops.
So I thought a lot and googled a lot about this topic and couldn't find an answer. I dont think it's possible at all because you have store the information which digits are already crossed out somewhere.
my code until now:
public static void main(String[] args) {
int n = 100;
int mark = 2;
System.out.print("Primes from 1 to "+n+": 2, ");
for (int i = 2; i <= n; i++) {
if(i % mark != 0){
System.out.print(i+", ");
mark = i;
}
}
}
-> So, i'm not allowed to do the "i % mark != 0" command with numbers which are multiples of the numbers i already printed but how am i supposed to make that clear without an array where i can delete numbers on indexes?
BUT if there is a solution I would be glad if someone could share it with me! :)
The solution can be in other programming languages, i can translate it to java myself if its possible.
Thank you in advance and best regards
Update: Thank you very much all of you, i really appreciate your help but I don't think it can be done with the basic structures. All the algorithms i have seen yet which print out primes by using basic structures are no sieve of eratosthenes. :(
回答1:
I'm taking back what I said earlier. Here it is, the "sieve" without arrays, in Haskell:
sieve limit = [n | n <- [2..limit], null [i | i <- [2..n-1], j <- [0,i..n], j==n]]
It is a forgetful sieve, and it is very very inefficient. Uses only additions, and integer comparisons. The list comprehensions in it can be re-coded as loops, in an imperative language. Or to put it differently, it moves counts like a sieve would, but without marking anything, and thus uses no arrays.
Of course whether you'd consider it a "true" sieve or not depends on what is your definition of a sieve. This one constantly recreates and abandons them. Or you could say it reimplements the rem
function. Which is the same thing to say, actually, and goes to the essence of why the sieve suddenly becomes so efficient when reuse - via arrays usually - becomes possible.
回答2:
The Sieve is about remembering the primes you found already. As far as I know there is no way to do this without arrays or lists and only with loops.
I checked some of the examples at RosettaCode at random and did not find one without an array and only loops.
If you add Classes and Methods as options you can come up with a recursive design:
public class Sieve
{
private int current;
private int max;
private Sieve parent;
public Sieve(int current, int max, Sieve parent )
{
this.current = current;
this.max = max;
this.parent = parent;
}
public static void main(String[] args)
{
int n = 100;
System.out.print("Primes from 1 to " + n + ":\n");
printPrimes(n);
}
private static void printPrimes(int i)
{
new Sieve(2,i,null).start();
}
private void start()
{
if(current <2 || max <2)
{
return;
}
if(this.current > max)
{
parent.print();
return;
}
for(int i = this.current+1;current<=max+1;i++)
{
if(this.testPrime(i))
{
new Sieve(i,this.max,this).start();
return;
}
}
}
private boolean testPrime(int i)
{
if(i%this.current != 0)
{
if(this.parent == null)
{
return true;
}
else
{
return this.parent.testPrime(i);
}
}
return false;
}
private void print()
{
if(this.parent != null)
{
this.parent.print();
}
System.out.print(" "+this.current);
}
}
This removes the array but uses Objects to store the Prime (each Sieve
holds one prime)
来源:https://stackoverflow.com/questions/26544714/sieve-of-eratosthenes-without-arrays