问题
C#:
char z = '\u201D';
int i = (int)z;
C++/CLI:
wchar_t z = '\u201D';
int i = (int)z;
In C# "i
" becomes, just as I expect, 8221 ($201D). In C++/CLI on the other hand, it becomes 65428 ($FF94). Can some kind soul explain this to me?
EDIT: Size of wchar_t
can not be of issue here, because:
C++/CLI:
wchar_t z = (wchar_t)8221;
int i = (int)z;
Here too, i
becomes 8221, so wchar_t
is indeed up to the game of holding a 16-bit integer on my system. Ekeforshus
回答1:
You want:
wchar_t z = L'\x201D';
from here. \u is undefined.
回答2:
According to wikipedia:
"The width of
wchar_t
is compiler-specific and can be as small as 8 bits. Consequently, programs that need to be portable across any C or C++ compiler should not use wchar_t for storing Unicode text. The wchar_t type is intended for storing compiler-defined wide characters, which may be Unicode characters in some compilers."
You shouldn't make any assumptions about how it's implemented.
来源:https://stackoverflow.com/questions/1826426/unicode-string-literals-in-c-sharp-vs-c-cli