Is there any way to control the concatenation of the blockproc output?

你说的曾经没有我的故事 提交于 2019-12-02 03:51:05

问题


This is a follow up to the question: Overlapping sliding window over an image using blockproc or im2col?

So by using the code :

B = blockproc(A, [1 1], @block_fun, 'BorderSize', [2 2], 'TrimBorder', false, 'PadPartialBlocks', true)

I was able to create an overlapping sliding window over my image and calculate the dct2 for each window. But the problem is that blockproc concatenates the output in a way that I cannot use. The output greatly depends on the block size and the size of the output matrix is different because of it every time.

My dct2 function creates a 1 x 200 vector for every block or window. So I assumed that if there are 64 blocks I should get something like 64 x 200 or 200 x 64 output, but I get something like 64 x 1600 or in case of larger blocks I get 15 x 400.

Looking into the blockproc function the problem is caused by

% write 4 corner blocks
b(1:ul_output_size(1),1:ul_output_size(2),:) = ul_output;
if ll_processed
    last_row_start = final_rows - size(ll_output,1) + 1;
    last_row_width = size(ll_output,2);
    b(last_row_start:end,1:last_row_width,:) = ll_output;
end
if ur_processed
    last_col_start = final_cols - size(ur_output,2) + 1;
    last_col_height = size(ur_output,1);
    b(1:last_col_height,last_col_start:end,:) = ur_output;
end
if lr_processed
    last_row_start = final_rows - size(ll_output,1) + 1;
    last_col_start = final_cols - size(ur_output,2) + 1;
    b(last_row_start:end,last_col_start:end,:) = lr_output;
end

Apparently, blockproc further divides the blocks into upper left, upper right, lower left and lower right and concatenates that result. And that is why I am getting all this mixed outputs.

I need the output of each block in its each row, for each window. Each window should just give me a 1x200 output, that I can feed into my classifier.

Can I force the output of blockproc in the way that I want it, just give the output of each block.

If not, I would really appreciate an alternative solution to have an overlapping sliding window over the image.

edit: would it be possible to save the blocks data using block_struct.data for every block into a cell array inside the function block_fun and then use that array to extract my features?

Thank you

edit:

B = blockproc(images_m{1}, [64 64], @(x)reshape(x.data(:),[1 1 numel(x.data)]), 'BorderSize', [10 10], 'TrimBorder', false, 'PadPartialBlocks', true, 'PadMethod', 'replicate');
imgs = {};
for i = 1:size(B,1)
    for j = 1:size(B,2)
        tempy = squeeze(B(i,j,:));
        tempy2 = reshape(tempy, [84 84]);
        feats{end+1} = block_dct2(tempy2); %calculates dct2 for the block and returns a 1*200 vector

    end
end

回答1:


Maybe reshape you data in the third dimension?

>> A = magic(3)

A =

     8     1     6
     3     5     7
     4     9     2

>> B = blockproc(A, [1 1], @(x)reshape(x.data(:),[1 1 numel(x.data)]), 'BorderSize', [1 1], 'TrimBorder', false, 'PadPartialBlocks', true);

>> whos B
  Name      Size             Bytes  Class     Attributes

  B         3x3x9              648  double  
>> squeeze(B(1,1,:))

ans =

     0
     0
     0
     0
     8
     3
     0
     1
     5

>> 



回答2:


An alternate using MAT2CELL:

function extractFeatures
images_m{1} = rand(128);
B = blockproc(images_m{1}, [64 64], @processBlock,...
    'BorderSize', [10 10], 'TrimBorder', false,...
    'PadPartialBlocks', true, 'PadMethod', 'replicate');

%B is 2x400 i.e 2x2 blocks of each block being a 1x200 feature vector
m = ones(1,size(B,1));
n = 200*ones(1,size(B,2)/200);
% The MAT2CELL help does a good job, just read it carefully and run the
% examples
feats = mat2cell(B,m,n);
feats = feats(:);

end

function feature = processBlock(bstruct)    
    % I dont know what block_dct2 does:
    %feature = block_dct2(bstruct.data);
    % So I'll put in a place holder which returns a 1x200 'feature'
    % for each overlapping image block
    feature = repmat(mean(bstruct.data(:)), [1 200]);
end


来源:https://stackoverflow.com/questions/29109241/is-there-any-way-to-control-the-concatenation-of-the-blockproc-output

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