zipfile

来源： https://stackoverflow.com/questions/54872560/zip-file-to-bytes-python-3

来源： https://stackoverflow.com/questions/41333168/how-to-send-a-zip-file-from-web-api-2-httpget

来源： https://stackoverflow.com/questions/63996368/extract-zip-file-in-sftp-using-c-sharp

来源： https://stackoverflow.com/questions/63996368/extract-zip-file-in-sftp-using-c-sharp

来源： https://stackoverflow.com/questions/61108954/how-to-unzip-multi-layered-zip-files-in-c-sharp

来源： https://stackoverflow.com/questions/61108954/how-to-unzip-multi-layered-zip-files-in-c-sharp

问题 Is there a noticeably faster alternative to Python 2.7.4 zipfile module (with ZIP_DEFLATED) for zipping a large number of files into a single zip file? I had a look at czipfile https://pypi.python.org/pypi/czipfile/1.0.0, but that appears to be focused on faster decrypting (not compressing). I am routinely having to process a large number of image files (~12,000 files of a combination of .exr and .tiff files) with each file between ~1MB - 6MB in size (and ~9 GB for all the files) into a

问题 Is there a noticeably faster alternative to Python 2.7.4 zipfile module (with ZIP_DEFLATED) for zipping a large number of files into a single zip file? I had a look at czipfile https://pypi.python.org/pypi/czipfile/1.0.0, but that appears to be focused on faster decrypting (not compressing). I am routinely having to process a large number of image files (~12,000 files of a combination of .exr and .tiff files) with each file between ~1MB - 6MB in size (and ~9 GB for all the files) into a

问题 i've made a PHP form which contains an input[type=file] that only accepts zip format files. the zip file successfully uploads when the form is submitted. i have also created a download link for admin to download the file which has uploaded by the user. the problem is when the file is downloaded it has this error with it => "the archive is either in unknown format or damaged" i would be thankful if you help me here is my code : if (!empty($_FILES)){ foreach ($_FILES as $key=>$file){ $fileName

问题 I want to unzip a specific named file located in a specific directory. The name of the file = happy.zip . The location = C:/Users/desktop/Downloads . I want to extract all the files to C:/Users/desktop/Downloads (the same location) I tried: import zipfile import os in_Zip = r"C:/Users/desktop/Downloads/happy.zip" outDir = r"C:/Users/desktop/Downloads" z = zipfile.ZipFile(in_Zip, 'r') z.extractall(outDir, pwd='1234!') z.close But I got: "TypeError: pwd: expected bytes, got str" 回答1: In Python