xom

Applying xpath on xml with default namespace with XOM

元气小坏坏 提交于 2019-12-10 15:27:27
问题 I have below XML which contains a default namespace <?xml version="1.0"?> <catalog xmlns="http://www.edankert.com/examples/"> <cd> <artist>Stoat</artist> <title>Future come and get me</title> </cd> <cd> <artist>Sufjan Stevens</artist> <title>Illinois</title> </cd> <cd> <artist>The White Stripes</artist> <title>Get behind me satan</title> </cd> </catalog> And Im running following code expecting some result in return Element rootElem = new Builder().build(xml).getRootElement(); xc =

Finding the exact location of an Element in a XML-Document

寵の児 提交于 2019-12-10 11:48:01
问题 I'm looking for a way to find the exact location of an Element within a XML-Document. I parse my Document with XOM and process it in the usual way. The tricky thing is, that in the XML document, some scripts are embedded (just text nodes) and in the case the scripts fail (parsing, logic, whatever) I want to report the user (which writes those scripts) the exact line number the script has been declared. The most ideal way would be something like this: int scriptLine = someElement

XPath Expression returns nothing for //element, but //* returns a count

懵懂的女人 提交于 2019-12-09 18:33:51
问题 I'm using XOM with the following sample data: Element root = cleanDoc.getRootElement(); //find all the bold elements, as those mark institution and clinic. Nodes nodes = root.query("//*"); <html xmlns="http://www.w3.org/1999/xhtml" xmlns:html="http://www.w3.org/1999/xhtml"> <head> <title>Patient Information</title> </head> </html> The following element returns many elements (from real data): //* but something like //head Returns nothing. If I run through the children of the root, the numbers

“Could not find a suitable SAX2 parser” when i try parsing XML with XOM Tutorial

女生的网名这么多〃 提交于 2019-12-06 14:31:15
问题 I'm trying to find a simple way to get XML content in my Android app. I gave XOM a try. Creating XML is no problem, but when i try to parse some... the emulator crashes with a force close. I have no idea where to look. I have the internet permissions set in the manifest. In debug/variables i can see "Could not find a suitable SAX2 parser" and in logcat something the same 07-22 12:27:51.565: INFO/System.out(683): debugger has settled (1337) 07-22 12:27:52.034: INFO/dalvikvm(683): Could not

“Could not find a suitable SAX2 parser” when i try parsing XML with XOM Tutorial

China☆狼群 提交于 2019-12-04 21:25:54
I'm trying to find a simple way to get XML content in my Android app. I gave XOM a try. Creating XML is no problem, but when i try to parse some... the emulator crashes with a force close. I have no idea where to look. I have the internet permissions set in the manifest. In debug/variables i can see "Could not find a suitable SAX2 parser" and in logcat something the same 07-22 12:27:51.565: INFO/System.out(683): debugger has settled (1337) 07-22 12:27:52.034: INFO/dalvikvm(683): Could not find method org.apache.xerces.impl.Version.getVersion, referenced from method nu.xom.Builder.<clinit> 07

Using XPath to extract XOM elements from documents with unnecessary namespaces

流过昼夜 提交于 2019-12-02 03:24:03
问题 I'm trying to parse some HTML returned by an external system with XOM. The HTML looks like this: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <body> <div> Help I am trapped in a fortune cookie factory </div> </body> </html> (Actually it's significantly messier, but it has this DOCTYPE declaration and these namespace and language declarations, and the

Using XPath to extract XOM elements from documents with unnecessary namespaces

情到浓时终转凉″ 提交于 2019-12-01 22:48:40
I'm trying to parse some HTML returned by an external system with XOM. The HTML looks like this: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <body> <div> Help I am trapped in a fortune cookie factory </div> </body> </html> (Actually it's significantly messier, but it has this DOCTYPE declaration and these namespace and language declarations, and the HTML above exhibits the same problem as the real HTML.) What I want to do is extract the content of

Java - Difference between for loop terminating expression

半城伤御伤魂 提交于 2019-12-01 18:14:23
I'm just curious: Is there a difference on speed and performance between this two loops implementation? Assume that size() method returns the length of the array,collection, or object that handles a group of elements (actually it's from XOM api). Implementation 1: int size = someArray.size(); for (int i = 0; i < size; i++) { // do stuff here } Implementation 2: for (int i = 0; i < someArray.size(); i++) { // do stuff here } From a performance point of view, there is little difference. This is because a loop can be optimized so that the size() lookup is inlined, resulting in very little

DTD download error while parsing XHTML document in XOM

柔情痞子 提交于 2019-11-29 04:33:13
I am trying to parse an HTML document with the doctype declared to use the transitional dtd as follows: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" " http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd "> When I do Builder.build on the document, I get the following exception: java.io.IOException: Server returned HTTP response code: 503 for URL: http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd at sun.net.www.protocol.http.HttpURLConnection.getInputStream(HttpURLConnection.java:1305) at org.apache.xerces.impl.XMLEntityManager.setupCurrentEntity(Unknown Source) at

Java How to extract a complete XML block

☆樱花仙子☆ 提交于 2019-11-27 14:13:18
Using this XML example: <A> <B> <id>0</id> </B> <B> <id>1</id> </B> </A> I want a simple method to extract the XML block of node B, returning the XML String: <B> <id>1</id> </B> To retrieve this node i should use some Java XPath library like XOM or Java XPath, but i couldn't find how to get the complete XML string. I found two equivalent answered questions using C#: C# How to extract complete xml node set and how can I extract an XML block from an XML document? Adding to lwburk's solution, to convert a DOM Node to string form, you can use a Transformer : private static String nodeToString(Node