xmlunit | 易学教程

Ignoring a particular attribute of a specific Node while comparing xml files using XMLUnit 2.X

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问题 I have two XML files:  <note id="ignoreThisAttribute_1"> <to>Experts</to> <from>Matrix</from> <heading id="dontIgnoreThisAttribute_1">Reminder</heading> <body>Help me with this problem</body> </note>  <note id="ignoreThisAttribute_2"> <to>Experts</to> <from>Matrix</from> <heading id="dontIgnoreThisAttribute_2">Reminder</heading> <body>Help me with this problem<

Groovy : Compare SOAP Response with XML file

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问题 I want to compare in groovy code my Soap Response with xml file ignoring order : Here is my code : import org.custommonkey.xmlunit.Stuff import org.xmlunit.Stuff //ExpectedString is my xml converted to text, same for ResponseString Diff diff = DiffBuilder.compare(ExpectedString) .withTest(ResponseString) .ignoreComments() .ignoreWhitespace() .checkForSimilar() .withNodeMatcher(new DefaultNodeMatcher(ElementSelectors.byName)) .build(); assertFalse("XML similar " + diff.toString(), diff

How do I ignore order of identical elements with XMLUnit's DetailedDifference?

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问题 I want to compare two xml files using XMLUnit. I would like the DetailedDiff to not report identical tags in different orders as differences. For example, if I created a DetailedDiff with these two snippets: <a><b/><c/></a> and <a><c/><b/></a> The DetailedDiff will create two Differences since the b and c tags are out of order. I have tried overriding element qualifiers but it doesn't result in any changes. Am I doing something wrong or is this impossible to do with XMLUnit? For reference

How do I ignore order of identical elements with XMLUnit's DetailedDifference?

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I want to compare two xml files using XMLUnit. I would like the DetailedDiff to not report identical tags in different orders as differences. For example, if I created a DetailedDiff with these two snippets: <a><b/><c/></a> and <a><c/><b/></a> The DetailedDiff will create two Differences since the b and c tags are out of order. I have tried overriding element qualifiers but it doesn't result in any changes. Am I doing something wrong or is this impossible to do with XMLUnit? For reference here's the code I'm using to compare two xml files (not including overrideElementQualifier calls). public

Ignoring a particular attribute of a specific Node while comparing xml files using XMLUnit 2.X

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I have two XML files:  <note id="ignoreThisAttribute_1"> <to>Experts</to> <from>Matrix</from> <heading id="dontIgnoreThisAttribute_1">Reminder</heading> <body>Help me with this problem</body> </note>  <note id="ignoreThisAttribute_2"> <to>Experts</to> <from>Matrix</from> <heading id="dontIgnoreThisAttribute_2">Reminder</heading> <body>Help me with this problem</body> </note> I have to ignore the attribute: id of Node: note while comparing these two files. I am using

Compare XML ignoring element order

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With XMLUnit 2 how do you compare two documents without taking the element order into account? I got this question for XMLUnit 1 , but apparently the new API in v2 doesn't have the mentioned method anymore. This is my current code: Diff diff = DiffBuilder.compare(expected) .withTest(actual) .ignoreComments() .ignoreWhitespace() .checkForSimilar() .build(); assertFalse(diff.hasDifferences()); Edit to Stefan Bodewigs comment: These are the two strings i compare with above snippet: String expected = "<root><foo>FOO</foo><bar>BAR</bar></root>"; String actual = "<root><bar>BAR</bar><foo>FOO</foo><

Are there any alternatives to XmlUnit?

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问题 I need to diff large directory structures containing generated .xml and .wsdl files. The generated .xml files differ in the order that child elements appear. The XmlUnit Diff.similar() method is supposed to handle this case: 'Two documents are considered to be "similar" if they contain the same elements and attributes regardless of order.' This is not the case, however. I took a .xml file, reversed the order of two child elements and XmlUnit says that they are not similar. XmlUnit is broken,

Are there any alternatives to XmlUnit?

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I need to diff large directory structures containing generated .xml and .wsdl files. The generated .xml files differ in the order that child elements appear. The XmlUnit Diff.similar() method is supposed to handle this case: 'Two documents are considered to be "similar" if they contain the same elements and attributes regardless of order.' This is not the case, however. I took a .xml file, reversed the order of two child elements and XmlUnit says that they are not similar. XmlUnit is broken, providing no more functionality than the built-in diff utility. Is there an alternative to XmlUnit that

Comparing similar xml files with XmlUnit with unordered tags (same tag name with different attributes)

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I am trying successfully XmlUnit, and is very helpful in my job. Now, I have a little problem, that I don't know how to solve. I have a java class, that has a Set, and when transforming it into XML, the elements inside can have any order. When I try these two files in XmlUnit it works (Diff says that they are similar): <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <Monitor> <AvailableMeasures> <MeasureDescriptorA name="netInput_mynetwork"></MeasureDescriptorA> <MeasureDescriptor name="netInput_myothernetwork"></MeasureDescriptor> </AvailableMeasures> </Monitor> <?xml version="1.0"

Compare two XML strings ignoring element order

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Suppose I have two xml strings <test> <elem>a</elem> <elem>b</elem> </test> <test> <elem>b</elem> <elem>a</elem> </test> How to write a test that compares those two strings and ignores the element order? I want the test to be as short as possible, no place for 10-line XML parsing etc. I'm looking for a simple assertion or something similar. I have this (which doesn't work) Diff diff = XMLUnit.compareXML(expectedString, actualString); XMLAssert.assertXMLEqual("meh", diff, true); user1121883 My original answer is outdated. If I would have to build it again i would use xmlunit 2 and xmlunit