word-count

How to extract the nth word and count word occurrences in a MySQL string?

霸气de小男生 提交于 2019-11-26 03:36:27
问题 I would like to have a mysql query like this: select <second word in text> word, count(*) from table group by word; All the regex examples in mysql are used to query if the text matches the expression, but not to extract text out of an expression. Is there such a syntax? 回答1: The following is a proposed solution for the OP's specific problem (extracting the 2nd word of a string), but it should be noted that, as mc0e's answer states, actually extracting regex matches is not supported out-of

WebForms UnobtrusiveValidationMode requires a ScriptResourceMapping for &#39;jquery&#39;. Please add a ScriptResourceMapping named jquery(case-sensitive)

怎甘沉沦 提交于 2019-11-26 03:34:48
问题 I\'m building a web application using Visual Studio 2012. I\'m attempting to add word count into my textbox. However after adding the the javascript codes and the html codes. I receive the error as stated above. Here is my javascript codeds Code : function validateLimit(obj, divID, maxchar) { objDiv = get_object(divID); if (this.id) obj = this; var remaningChar = maxchar - trimEnter(obj.value).length; if (objDiv.id) { objDiv.innerHTML = remaningChar + \" characters left\"; } if (remaningChar

How to count words in MySQL / regular expression replacer?

守給你的承諾、 提交于 2019-11-26 02:38:42
问题 How can I, in a MySQL query, have the same behaviour as the Regex.Replace function (for instance in .NET/C#)? I need that because, as many people, I would like to count the number of words in a field. However, I\'m not satisfied with the following answer (given several times on that site): SELECT LENGTH(name) - LENGTH(REPLACE(name, \' \', \'\') +1 FROM table Because it doesn\'t give good results when there are more that one space between two words. By the way, I think the Regex.Replace

Word frequency count Java 8

扶醉桌前 提交于 2019-11-26 01:47:13
问题 How to count the frequency of words of List in Java 8? List <String> wordsList = Lists.newArrayList(\"hello\", \"bye\", \"ciao\", \"bye\", \"ciao\"); The result must be: {ciao=2, hello=1, bye=2} 回答1: I want to share the solution I found because at first I expected to use map-and-reduce methods, but it was a bit different. Map<String, Long> collect = wordsList.stream().collect(groupingBy(Function.identity(), counting())); Or for Integer values: Map<String, Integer> collect = wordsList.stream()