wcf-web-api

I have a problem reading uploaded XML file to the string instead of file. My problem is that when I try to access the stream ( var stream = part.ContentReadStream ) then it's closed. I have feeling that it is accessing closed file stream. Am I using MultipartFormDataStreamProvider incorrectly? File size is only few kilobytes, so that should not be a problem. [WebInvoke(Method = "POST", UriTemplate = "{importFile}")] public HttpResponseMessage Upload(string importFile, HttpRequestMessage request) { if (!request.Content.IsMimeMultipartContent()) { throw new HttpResponseException(HttpStatusCode

I am using post method in that method i want to pass entire Json in string like this way {Data:" JsonArray"} in Jssonarray I want to pass this value { "version" : 2, "query" : "Companies, CA", "begin" : 1, "end" : 3, "totalResults" : 718, "pageNumber" : 0, "results" : [ { "company" : "ABC Company Inc.", "city" : "Sacramento", "state" : "CA" } , { "company" : "XYZ Company Inc.", "city" : "San Francisco", "state" : "CA" } , { "company" : "KLM Company Inc.", "city" : "Los Angeles", "state" : "CA" } ] } When i pass this I am getting 500 internal Error Please help me how to pass Entire Json in a

How does WCF REST (and WCF WebApi) map a Uri to the correct service endpoint? Within the context of WCF WebApi Preview 4: Inside a custom delegating channel, I would like to find the associated route prefix or service Type based on the incoming HttpRequestMessage.RequestUri. So for instance, RouteTable.Routes.MapServiceRoute<ManagersResource>("employees/managers", config); RouteTable.Routes.MapServiceRoute<EmployeesResource>("employees", config); Say a request comes in for http://server/employees/John How does WCF map this to the correct endpoint? By the time the ResourceFactoryProvider has

Is there any way to upload a file to WCF web API endpoint? If so, how can I access Network Stream to read data? Any help is very much appreciated. Thanks. Assuming you are talking about on the client side: One way to do it is to create a FileContent class that derives from HttpContent. In the overrides you will be given the NetworkStream when the HTTPClient is ready to receive the stream. If you are asking about the server side, then you can simply get hold of the HTTPRequestMessage and access the httpRequestMessage.Content.ContentReadStream property. Update By default the WCF Transport is

I have created an OData service and now I am trying to consume this service at client side. I wants to create an expression such as for the below url in the c# query expression- http://odata.org/Product-Service/Product(150) The above url is working fine in browsers but I want to create query expression in the C# for the above url. Any help would be greatly appreciable. You could use a DataServiceContext + DataServiceQuery in System.Data.Services.Client to hit the Url. Remember no query is executed until the call to First() due to lazy loading. var context = new DataServiceContext(new Uri("http

I have WebApi controllers that end with the "Api" suffix in their names (For ex: StudentsApiController, InstructorsApiController). I do this to easily differentiate my MVC controllers from WebApi controllers. I want my WebApi routes to look similar to http://localhost:50009/api/students/5 and not http://localhost:50009/api/studentsapi/5 . Currently to achieve this, I am setting up routes like routes.MapHttpRoute( name: "GetStudents", routeTemplate: "api/students/{id}", defaults: new { controller = "StudentsApi", id = RouteParameter.Optional }); routes.MapHttpRoute( name: "GetInstructors",

I was using a method like below on the previous versions of WCF Web API: // grab the posted stream Stream stream = request.Content.ContentReadStream; // write it to using (FileStream fileStream = File.Create(fullFileName, (int)stream.Length)) { byte[] bytesInStream = new byte[stream.Length]; stream.Read(bytesInStream, 0, (int)bytesInStream.Length); fileStream.Write(bytesInStream, 0, bytesInStream.Length); } But on the preview 6, HttpRequestMessage.Content.ContentReadStream property is gone. I believe that it now should look like this one: // grab the posted stream System.Threading.Tasks.Task