variadic

Let's say, I have min() (just for example) a variadic function to define the smallest value from multiple values provided. If the caller don't provided any parameter, I want to halt compile process (as this would be the bug in the caller, not error in my function). How to do that? Calling a function which has variadic parameter and passing no arguments is valid by the language spec. So you can't make it a compile-time error. However, you may modify the signature of your function to have a non-variadic and a variadic parameter, and then calling it with no arguments would indeed be a compile

How can variadic functions like printf find out the number of arguments they got? The amount of arguments obviously isn't passed as a (hidden) parameter (see a call to printf in asm example here ). What's the trick? The trick is that you tell them somehow else. For printf you have to supply a format string which even contains type information (which might be incorrect though). The way to supply this information is mainly user-contract and often error-prone. As for calling conventions: Usually the arguments are pushed onto the stack from left to right and then the backjump address at last. The

I'm trying to write a variadic function composition function. Which is basically the (.) except that the second argument function is variadic. This should allow expressions like: map even . zipWith (+) or just map even . zipWith Currently what I've reached works if I add IncoherentInstances and requires a non-polymorphic instance for the first argument function. {-# LANGUAGE FlexibleInstances, OverlappingInstances, MultiParamTypeClasses, FunctionalDependencies, UndecidableInstances, KindSignatures #-} class Comp a b c d | c -> d where comp :: (a -> b) -> c -> d instance Comp a b (a :: *) (b ::

Let's say I have a few structs like this: struct MyStruct1 { inline void DoSomething() { cout << "I'm number one!" << endl; } }; struct MyStruct2 { static int DoSomething() { cout << "I'm the runner up." << endl; return 1; } }; struct MyStruct3 { void (*DoSomething)(); MyStruct3() { DoSomething = &InternalFunction; } static void InternalFunction() { cout << "I'm the tricky loser." << endl; } }; As you can see, for all three structs, I can call DoSomething() on an object of that struct and have it work (though this is achieved differently for each struct): MyStruct1 a; MyStruct2 b; MyStruct3 c;

Can we pass variable number of arguments to a function in c? Preet Sangha Here is an example: #include <stdlib.h> #include <stdarg.h> #include <stdio.h> int maxof(int, ...) ; void f(void); int main(void){ f(); exit(EXIT SUCCESS); } int maxof(int n_args, ...){ register int i; int max, a; va_list ap; va_start(ap, n_args); max = va_arg(ap, int); for(i = 2; i <= n_args; i++) { if((a = va_arg(ap, int)) > max) max = a; } va_end(ap); return max; } void f(void) { int i = 5; int j[256]; j[42] = 24; printf("%d\n", maxof(3, i, j[42], 0)); } If it is a function that accepts a variable number of arguments

My guess is the answer to this question is no, but it would be awesome if there was a way. To clarify, assume I have the following macro: #define MY_VARIADIC_MACRO(X...) // Does some stuff here in the macro definition What I would like to do is somehow perform stringification on all the variables of X before passing it to a variadic function; the keyword here is before. I realize there's no way to really access the individual arguments from within the macro definition, but is there a way to stringify all the arguments, with maybe something like the following? #define MY_VARIADIC_MACRO(X...)

Question is simple, how would I implement a function taking a variable number of arguments (alike the variadic template), however where all arguments have the same type, say int. I was thinking about something alike this; void func(int... Arguments) Alternatively wont a recursive static assert on the types work? A possible solution is to make the parameter type a container that can be initialized by a brace initializer list, such as std::initializer_list<int> or std::vector<int> . For example : #include <iostream> #include <initializer_list> void func(std::initializer_list<int> a_args) { for