use-strict

Is “use strict” Safe for Live Sites?

由 与世无争的帅哥 提交于 2019-11-29 17:34:50
问题 "use strict"; seems awesome, and we'd really like to use it at our shop. However, we just want it so that we (the developers) can find strictness-issues; we very much DO NOT want to make our site break for our actual customers when it was working fine before. Now, we could just use some server-side logic to achieve this: {% if debug %}<script>"use strict";</script>{% endif %} ... except that "use strict" operates on a file-by-file basis, so that won't actually work (well, unless we start

How does “use strict” modify the rules for “this” in Javascript?

由 做~自己de王妃 提交于 2019-11-29 15:59:13
I'm trying to understand what rule for "this" that "use strict"; modifies in the below case. After reading ( http://unschooled.org/2012/03/understanding-javascript-this/ ) my best guess is that since the functon isStrictModeOn() is not "attached" to anything, this refers to null. Which is suppose to be a more sensible alternative to Javascript just attaching the this to the global object. Is that the correct interpretation of the change that "use strict" is making in this case? http://www.novogeek.com/post/ECMAScript-5-Strict-mode-support-in-browsers-What-does-this-mean.aspx function

John Resig's simple class instantiation and “use strict”

由 断了今生、忘了曾经 提交于 2019-11-29 02:20:25
Reference : http://ejohn.org/blog/simple-class-instantiation/ // makeClass - By John Resig (MIT Licensed) function makeClass(){ return function(args){ if ( this instanceof arguments.callee ) { if ( typeof this.init == "function" ) this.init.apply( this, args.callee ? args : arguments ); } else return new arguments.callee( arguments ); }; } I was wondering, if there are any ECMAScript 5 compliant way to implement the same functionality. The problem is, accessing arguments.callee is deprecated in strict mode. As I understand it arguments.callee isn't deprecated in strict mode, in which case you

How does “use strict” modify the rules for “this” in Javascript?

由 假装没事ソ 提交于 2019-11-28 09:37:08
问题 I'm trying to understand what rule for "this" that "use strict"; modifies in the below case. After reading (http://unschooled.org/2012/03/understanding-javascript-this/) my best guess is that since the functon isStrictModeOn() is not "attached" to anything, this refers to null. Which is suppose to be a more sensible alternative to Javascript just attaching the this to the global object. Is that the correct interpretation of the change that "use strict" is making in this case? http://www

Does “use strict” in the constructor extend to prototype methods?

由 女生的网名这么多〃 提交于 2019-11-28 08:03:37
问题 I'm trying to figure out whether the definition of 'use strict' extends to the prototype methods of the constructor. Example: var MyNamespace = MyNamespace || {}; MyNamespace.Page = function() { "use strict"; }; MyNamespace.Page.prototype = { fetch : function() { // do I need to use "use strict" here again? } }; According to Mozilla you can use it as: function strict(){ "use strict"; function nested() { return "And so am I!"; } return "Hi! I'm a strict mode function! " + nested(); } Does it

John Resig's simple class instantiation and “use strict”

由 爷，独闯天下 提交于 2019-11-27 21:55:49
问题 Reference : http://ejohn.org/blog/simple-class-instantiation/ // makeClass - By John Resig (MIT Licensed) function makeClass(){ return function(args){ if ( this instanceof arguments.callee ) { if ( typeof this.init == "function" ) this.init.apply( this, args.callee ? args : arguments ); } else return new arguments.callee( arguments ); }; } I was wondering, if there are any ECMAScript 5 compliant way to implement the same functionality. The problem is, accessing arguments.callee is deprecated

How do you find out the caller function in JavaScript when use strict is enabled?

由 |▌冷眼眸甩不掉的悲伤 提交于 2019-11-27 19:17:30
Is it possible to see the callee/caller of a function when use strict is enabled? 'use strict'; function jamie (){ console.info(arguments.callee.caller.name); //this will output the below error //uncaught TypeError: 'caller', 'callee', and 'arguments' properties may not be accessed on strict mode functions or the arguments objects for calls to them }; function jiminyCricket (){ jamie(); } jiminyCricket (); p.s.w.g For what it's worth, I agree with the comments above. For whatever problem you're trying to solve, there are usually better solutions. However, just for illustrative purposes, here's

How is the 'use strict' statement interpreted in Node.js? [duplicate]

由 纵饮孤独 提交于 2019-11-27 17:08:37
This question already has an answer here: What does “use strict” do in JavaScript, and what is the reasoning behind it? 27 answers I have started to explore the Node.js and wrote many demo web application, to understand the flow of Node.js, Express.js, jade, etc.. But one thing I came across recently, is the statement "use strict" as the first line inside every function and every .js file. How exactly is it is interpreted by Node.js? Amol M Kulkarni "use strict"; Basically it enables the strict mode. Strict Mode is a feature that allows you to place a program, or a function, in a "strict"

How is the 'use strict' statement interpreted in Node.js? [duplicate]

由 江枫思渺然 提交于 2019-11-26 22:31:53
问题 This question already has an answer here: What does “use strict” do in JavaScript, and what is the reasoning behind it? 27 answers I have started to explore the Node.js and wrote many demo web application, to understand the flow of Node.js, Express.js, jade, etc.. But one thing I came across recently, is the statement "use strict" as the first line inside every function and every .js file. How exactly is it is interpreted by Node.js? 回答1: "use strict"; Basically it enables the strict mode.

How do you find out the caller function in JavaScript when use strict is enabled?

由 笑着哭i 提交于 2019-11-26 22:16:19
问题 Is it possible to see the callee/caller of a function when use strict is enabled? 'use strict'; function jamie (){ console.info(arguments.callee.caller.name); //this will output the below error //uncaught TypeError: 'caller', 'callee', and 'arguments' properties may not be accessed on strict mode functions or the arguments objects for calls to them }; function jiminyCricket (){ jamie(); } jiminyCricket (); 回答1: For what it's worth, I agree with the comments above. For whatever problem you're
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