urlopen

Use “byte-like object” from urlopen.read with JSON?

时光毁灭记忆、已成空白 提交于 2019-12-03 10:33:33
Just trying to test out very simple Python JSON commands, but I'm having some trouble. urlopen('http://www.similarsitesearch.com/api/similar/ebay.com').read() should output '{"num":20,"status":"ok","r0":"http:\\/\\/www.propertyroom.com\\/","r1":"http:\\/\\/www.ubid.com\\/","r2":"http:\\/\\/www.bidcactus.com\\/","r3":"http:\\/\\/www.etsy.com\\/","r4":"http:\\/\\/us.ebid.net\\/","r5":"http:\\/\\/www.bidrivals.com\\/","r6":"http:\\/\\/www.ioffer.com\\/","r7":"http:\\/\\/www.shopgoodwill.com\\/","r8":"http:\\/\\/www.beezid.com\\/","r9":"http:\\/\\/www.webidz.com\\/","r10":"http:\\/\\/www

python urllib2 urlopen response

大城市里の小女人 提交于 2019-12-03 04:51:04
python urllib2 urlopen response: <addinfourl at 1081306700 whose fp = <socket._fileobject object at 0x4073192c>> expected: {"token":"mYWmzpunvasAT795niiR"} You need to bind the resultant file-like object to a variable, otherwise the interpreter just dumps it via repr : >>> import urllib2 >>> urllib2.urlopen('http://www.google.com') <addinfourl at 18362520 whose fp = <socket._fileobject object at 0x106b250>> >>> >>> f = urllib2.urlopen('http://www.google.com') >>> f <addinfourl at 18635448 whose fp = <socket._fileobject object at 0x106b950>> To get the actual data you need to perform a read() .

How do I set cookies using Python urlopen?

非 Y 不嫁゛ 提交于 2019-12-03 03:58:54
I am trying to fetch an html site using Python urlopen. I am getting this error: HTTPError: HTTP Error 302: The HTTP server returned a redirect error that would lead to an infinite loop The code: from urllib2 import Request request = Request(url) response = urlopen(request) I understand that the server redirects to another URL and that it is looking for a cookie. How do I set the cookie it is looking for so I can read the html? Here's an example from Python documentation , adjusted to your code: import cookielib, urllib2 cj = cookielib.CookieJar() opener = urllib2.build_opener(urllib2

How to set TCP_NODELAY flag when loading URL with urllib2?

余生颓废 提交于 2019-12-01 15:12:12
I am using urllib2 for loading web-page, my code is: httpRequest = urllib2.Request("http:/www....com") pageContent = urllib2.urlopen(httpRequest) pageContent.readline() How can I get hold of the socket properties to set TCP_NODELAY ? In normal socket I would be using function: socket.setsockopt(socket.IPPROTO_TCP, socket.TCP_NODELAY, 1) If you need to access to such low level property on the socket used, you'll have to overload some objects. First, you'll need to create a subclass of HTTPHandler , that in the standard library do : class HTTPHandler(AbstractHTTPHandler): def http_open(self, req

Again urllib.error.HTTPError: HTTP Error 400: Bad Request

别来无恙 提交于 2019-12-01 03:43:02
Hy! I tried to open web-page, that is normally opening in browser, but python just swears and does not want to work. import urllib.request, urllib.error f = urllib.request.urlopen('http://www.booking.com/reviewlist.html?cc1=tr;pagename=sapphire') And another way import urllib.request, urllib.error opener=urllib.request.build_opener() f=opener.open('http://www.booking.com/reviewlist.html?cc1=tr;pagename=sapphi re') Both options give one type of error: Traceback (most recent call last): File "<stdin>", line 1, in <module> File "C:\Python34\lib\urllib\request.py", line 461, in open response =

Again urllib.error.HTTPError: HTTP Error 400: Bad Request

雨燕双飞 提交于 2019-12-01 01:06:21
问题 Hy! I tried to open web-page, that is normally opening in browser, but python just swears and does not want to work. import urllib.request, urllib.error f = urllib.request.urlopen('http://www.booking.com/reviewlist.html?cc1=tr;pagename=sapphire') And another way import urllib.request, urllib.error opener=urllib.request.build_opener() f=opener.open('http://www.booking.com/reviewlist.html?cc1=tr;pagename=sapphi re') Both options give one type of error: Traceback (most recent call last): File "

Web scraping urlopen in python

雨燕双飞 提交于 2019-11-30 22:00:18
I am trying to get the data from this website: http://www.boursorama.com/includes/cours/last_transactions.phtml?symbole=1xEURUS It seems like urlopen don't get the html code and I don't understand why. It goes like: html = urllib.request.urlopen("http://www.boursorama.com/includes/cours/last_transactions.phtml?symbole=1xEURUS") print (html) My code is right, I get the html source of other webpages with the same code, but it seems like it doesn't recognise this address. it prints: b'' Maybe another library is more appropriate? Why urlopen doesn't return the html code of the webpage? help thanks

Web scraping urlopen in python

痴心易碎 提交于 2019-11-30 17:42:06
问题 I am trying to get the data from this website: http://www.boursorama.com/includes/cours/last_transactions.phtml?symbole=1xEURUS It seems like urlopen don't get the html code and I don't understand why. It goes like: html = urllib.request.urlopen("http://www.boursorama.com/includes/cours/last_transactions.phtml?symbole=1xEURUS") print (html) My code is right, I get the html source of other webpages with the same code, but it seems like it doesn't recognise this address. it prints: b'' Maybe

Preventing a “hidden” redirect with urlopen() in Python

点点圈 提交于 2019-11-30 16:01:01
问题 I am using BeautifulSoup for web scraping and I am having problems with a particular type of website when using urlopen . Every item on the website has its own unique page and the item comes in different formats ( ex: 500 mL, 1L, 2L,... ). When I open the URL of the product ( www.example.com/product1 ) using my Internet Browser, I would see a picture of the 500 mL format, information about it ( price, quantity, flavor, etc. ) and a list of all the other formats available for this specific

timeout for urllib2.urlopen() in pre Python 2.6 versions

情到浓时终转凉″ 提交于 2019-11-30 04:27:27
The urllib2 documentation says that timeout parameter was added in Python 2.6. Unfortunately my code base has been running on Python 2.5 and 2.4 platforms. Is there any alternate way to simulate the timeout? All I want to do is allow the code to talk the remote server for a fixed amount of time. Perhaps any alternative built-in library? (Don't want install 3rd party, like pycurl) you can set a global timeout for all socket operations (including HTTP requests) by using: socket.setdefaulttimeout() like this: import urllib2 import socket socket.setdefaulttimeout(30) f = urllib2.urlopen('http:/