urllib

问题 I'm trying to search the world wide web for this answer, but I feel there answer may be no. I'm using Python 3.5 and a library called urllib.request with a method called urllib.request.urlopen(url) to open a link and download a file. It would be nice to have some kind of measure of progress for this, as the file(s) are over 200MB. I'm looking at the API here, and don't see any kind of parameter with a hook. Here's my code: downloadURL = results[3] #got this from code earlier up rel_path =

问题 I recently started working on a program in python which allows the user to conjugate any verb easily. To do this, I am using the urllib module to open the corresponding conjugations web page. For example, the verb "beber" would have the web page: "http://www.spanishdict.com/conjugate/beber" To open the page, I use the following python code: source = urllib.urlopen("http://wwww.spanishdict.com/conjugate/beber").read() This source does contain the information that I want to parse. But, when I

问题 I recently started working on a program in python which allows the user to conjugate any verb easily. To do this, I am using the urllib module to open the corresponding conjugations web page. For example, the verb "beber" would have the web page: "http://www.spanishdict.com/conjugate/beber" To open the page, I use the following python code: source = urllib.urlopen("http://wwww.spanishdict.com/conjugate/beber").read() This source does contain the information that I want to parse. But, when I

问题 I'm trying to make a request to the GitHub API with Python 3 urllib to create a release, but I made some mistake and it fails with an exception: Traceback (most recent call last): File "./a.py", line 27, in <module> 'Authorization': 'token ' + token, File "/usr/lib/python3.6/urllib/request.py", line 223, in urlopen return opener.open(url, data, timeout) File "/usr/lib/python3.6/urllib/request.py", line 532, in open response = meth(req, response) File "/usr/lib/python3.6/urllib/request.py",

问题 I'm trying to make a request to the GitHub API with Python 3 urllib to create a release, but I made some mistake and it fails with an exception: Traceback (most recent call last): File "./a.py", line 27, in <module> 'Authorization': 'token ' + token, File "/usr/lib/python3.6/urllib/request.py", line 223, in urlopen return opener.open(url, data, timeout) File "/usr/lib/python3.6/urllib/request.py", line 532, in open response = meth(req, response) File "/usr/lib/python3.6/urllib/request.py",

问题 I'm trying to make a request to the GitHub API with Python 3 urllib to create a release, but I made some mistake and it fails with an exception: Traceback (most recent call last): File "./a.py", line 27, in <module> 'Authorization': 'token ' + token, File "/usr/lib/python3.6/urllib/request.py", line 223, in urlopen return opener.open(url, data, timeout) File "/usr/lib/python3.6/urllib/request.py", line 532, in open response = meth(req, response) File "/usr/lib/python3.6/urllib/request.py",

问题 Use urllib to read the HTML from the data files below, extract the href= vaues from the anchor tags, scan for a tag that is in a particular position relative to the first name in the list, follow that link and repeat the process a number of times and report the last name you find. This is HTML link for data http://py4e-data.dr-chuck.net/known_by_Caragh.html So I have to find the link at position 18 (the first name is 1). Follow that link. Repeat this process 7 times. The answer is the last

问题 Use urllib to read the HTML from the data files below, extract the href= vaues from the anchor tags, scan for a tag that is in a particular position relative to the first name in the list, follow that link and repeat the process a number of times and report the last name you find. This is HTML link for data http://py4e-data.dr-chuck.net/known_by_Caragh.html So I have to find the link at position 18 (the first name is 1). Follow that link. Repeat this process 7 times. The answer is the last

来源： https://stackoverflow.com/questions/64640225/the-urllib-request-returns-empty-data-while-the-same-request-in-postman-returns

来源： https://stackoverflow.com/questions/39287669/handling-connectionreseterror