url

问题 I completely stuck with slider with url links inside the Array. How to make this code run appropriate? This is it: https://codepen.io/konradszymanski/pen/VwvLgYG?editors=0110 or here is html: <script src='https://kit.fontawesome.com/a076d05399.js'></script> <div class="container"> <button class="left" onclick="" ><i class='fas fa-angle-left'></i></button> <button class="right" onclick="next()"><i class='fas fa-angle-right'></i></button> </div> and js: var images = [{img: "https://upload

问题 I am running php spark serve to run a codeigniter 4 app locally. if my $base_url have a port number, all my assets wont load, but it will if i remove the port number This wont load my assets public $baseURL = 'http://localhost:8080/folder_name'; This will load my assets public $baseURL = 'http://localhost/folder_name'; Any suggestion as to why and how to fix it? 回答1: i hope my answer is not late. since codeigniter 4 used spark server and there is many update. Just put your asset file to

问题 I'm looking for a way to compare two urls. I can do: URI('http://www.test.com/blabla').host to have the base name, but this not reliable. For example: URI('http://www.test.com/blabla').host == URI('http://test.com/blabla').host returns false , but they can be the same site. To have the IP address is not reliable too because if I do: IPSocket.getaddress(URI('http://hello.herokuapp.com').host) == IPSocket.getaddress(URI('http://test.herokuapp.com').host) It returns true , but they are not the

问题 I'm looking for a way to compare two urls. I can do: URI('http://www.test.com/blabla').host to have the base name, but this not reliable. For example: URI('http://www.test.com/blabla').host == URI('http://test.com/blabla').host returns false , but they can be the same site. To have the IP address is not reliable too because if I do: IPSocket.getaddress(URI('http://hello.herokuapp.com').host) == IPSocket.getaddress(URI('http://test.herokuapp.com').host) It returns true , but they are not the

问题 fellow programmers who lurks here at Stack Overflow. Today's question: How can I get the absolute baseUrl in Spring MVC Framework, from startup? I'm working with Spring MVC Framework for an application, and I'm in this situation: Let's say that I need to make objects of class Foo, inserted into a list. Every object contains an unique self-link (I'm using org.springframework.hateoas.Link for the real application, but that's beside the point). Example code: class Foo{ private int ID; private

问题 I am trying to load a MySQL jar dynamically in code but I am unsure about the format of the Windows path name. Is what I am using below correct, for loading a .jar from a thumbdrive? URL u = new URL("jar:file:G:/mysql-connector-java-5.1.15.jar!/"); URLClassLoader ucl = new URLClassLoader(new URL[] { u }); Now, this is not the same as the traditional path that you see in Java tutorials: URL url = new URL("file:/g:/mysql-connector-java-5.1.15.jar"); For the answer, I am looking for

问题 We have a small feature on our site which allows users to upload a profile picture. This picture will then be stored in our Postgres database as a base-64 encoded string. My question concerns the data scheme used in an <img> URL to render a base-64 encoded string, e.g. <img src="data:image/gif;base64,iVBORw0KGgo ..."> ^^^ but what if we don't know the extension? We plan on simply storing a base-64 blob and nothing else. But in this case, how could we know what extension was used in the

问题 Another question on URL parameters... sorry. Actually, I've been searching a lot about how to solve this, here and pretty much everywhere else, and I found absolutely nothing. Zero! Really appreciate if someone can give me a hand. Here's the thing, I'm exporting a google sheet to pdf with the following URL code. var url = "https://docs.google.com/spreadsheets/d/"+ssID+"/export"+ "?format=pdf&"+ "size=7&"+ "portrait=false&"+ // "zoom_scale=130&"+ "top_margin=0.00&"+ "bottom_margin=0.00&"+

问题 I want to base64_encode the parameters I send over the url. Send: <?php $product = array("productID"=>"13776", "name"=>"something", "availability"=>"1000"); $url_details = "?id=" . base64_encode(http_build_query($product)); ?> <a href="details.php<?php echo $url_details; ?>" class="btn btn-primary btn-lg" role="button">Details</a> Receive: <?php $details = base64_decode($_GET["id"]); // $product = what is the best way to reconstruct the array from $details? ?> <p> Name: <?php echo $products[

问题 Follow on from this question: Can i over-ride IE enterprise mode from HTML? I succeeded, in hosting a D3 SVG visualisation on my company sharepoint site. The Initial Issue: My internal company sharepoint site has enterprise mode settings in IE that was forcing me from IE11 into an IE8 environment per my console: HTML1122: Internet Explorer is running in Enterprise Mode emulating IE8. The workaround: Connect to site via the SSL in the browser, not via http/https URL. The connection looks