unreachable-statement

Llvm Remove Terminator Instruction

由 走远了吗. 提交于 2019-12-11 20:46:51
问题 I want to remove an UnreachableInst since a previous transformation has made it reachable. However, calling eraseFromParent() gives me a malformed BasicBlock since the UnreachableInst is the terminator of its BasicBlock. How do I fix the BasicBlock to terminate at the instruction previous to the UnreachableInst? 回答1: Every basic block must end with a terminator. I think that the most straightforward way to remove the unreachable instruction, then, is to replace it with another terminator -

Javacc Unreachable Statement

由 两盒软妹~` 提交于 2019-12-09 23:11:06
问题 In my grammar there are production rules for expressions and fragments which originally contained indirect left recursion. This is the rules after I removed the recursion from them. String expression() #Expression : {String number; Token t;} { number = fragment() ( (t = <Mult_Sign> number = fragment()) ) {return number;} } String fragment() #void : {String t;} { t = identifier() {return t;} | t = number() {return t;} | (<PLUS> | <MINUS> ) fragment() | <LBR> expression() <RBR> } These

Selenium UnreachableBrowserException - Java

由 孤者浪人 提交于 2019-12-08 12:52:19
问题 System.setProperty("webdriver.chrome.driver","D:/chromedriver.exe"); WebDriver driver = new ChromeDriver(); driver.navigate().to("https://link"); driver.findElement(By.cssSelector("#username")).sendKeys("id"); driver.findElement(By.cssSelector("#password")).sendKeys("pass"); driver.findElement(By.cssSelector("#clientName")).sendKeys("name"); driver.findElement(By.cssSelector("#submitButton")).click(); System.out.println("Okay !"); I set property for Chrome Driver. When I run it gives an error

Javacc Unreachable Statement

由 ▼魔方 西西 提交于 2019-12-04 15:18:19
In my grammar there are production rules for expressions and fragments which originally contained indirect left recursion. This is the rules after I removed the recursion from them. String expression() #Expression : {String number; Token t;} { number = fragment() ( (t = <Mult_Sign> number = fragment()) ) {return number;} } String fragment() #void : {String t;} { t = identifier() {return t;} | t = number() {return t;} | (<PLUS> | <MINUS> ) fragment() | <LBR> expression() <RBR> } These production rules are used when trying to parse a condition in the grammar. However the ordering of the

Unreachable statement error using while loop in java [duplicate]

由 佐手、 提交于 2019-12-02 04:25:32
问题 This question already has answers here : Closed 6 years ago . Possible Duplicate: Why is this code giving an “Unreachable Statement” error? This seems very easy question, I found this question in one book. If anyone help me to figure out why I'm getting error. do { System.out.print("inside do"); } while (false); while (false) { // error System.out.print("inside while"); } System.out.print("outside"); I thought, and according to me, output should be inside dooutside . But, it is showing

Unreachable statement error using while loop in java [duplicate]

由 Deadly 提交于 2019-12-02 00:56:03
Possible Duplicate: Why is this code giving an “Unreachable Statement” error? This seems very easy question, I found this question in one book. If anyone help me to figure out why I'm getting error. do { System.out.print("inside do"); } while (false); while (false) { // error System.out.print("inside while"); } System.out.print("outside"); I thought, and according to me, output should be inside dooutside . But, it is showing Compiler Error : Unreachable Statement . Then, I tried to figure out, why, it is showing Compilation error : Unreachable Statement* . So, I change the above code like this

Why does a Java Compiler not produce an unreachable statement error for an unreachable then statement?

由 梦想与她 提交于 2019-11-29 04:22:57
问题 If I try to compile for(;;) { } System.out.println("End"); The Java compiler produces an error saying Unreachable statement . But if I add another " unreachable "(according to me) break statement and make it: for(;;) { if(false) break; } System.out.println("End"); It compiles. Why does it not produce an error? 回答1: The behaviour is defined in the JLS description of unreachable statements: The then-statement is reachable iff the if-then statement is reachable. So the compiler determines that

I get the error “Unreachable statement” return in android

由 落花浮王杯 提交于 2019-11-26 09:14:21
问题 Why do I get the error that line 92 is an unreachable statement? The error is in this line: final RadioButton r1 = (RadioButton) getView().findViewById(R.id.radio1); Code: public class TabFragmentA extends Fragment { @Override public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { if (container == null) { return null; } return (RelativeLayout) inflater.inflate(R.layout.tab_layout_a, container, false); final RadioButton r1 = (RadioButton) getView()

Why does Java have an “unreachable statement” compiler error?

由 亡梦爱人 提交于 2019-11-26 02:07:16
I often find when debugging a program it is convenient, (although arguably bad practice) to insert a return statement inside a block of code. I might try something like this in Java .... class Test { public static void main(String args[]) { System.out.println("hello world"); return; System.out.println("i think this line might cause a problem"); } } of course, this would yield the compiler error. Test.java:7: unreachable statement I could understand why a warning might be justified as having unused code is bad practice. But I don't understand why this needs to generate an error. Is this just

Why does Java have an “unreachable statement” compiler error?

由 空扰寡人 提交于 2019-11-26 01:01:00
问题 I often find when debugging a program it is convenient, (although arguably bad practice) to insert a return statement inside a block of code. I might try something like this in Java .... class Test { public static void main(String args[]) { System.out.println(\"hello world\"); return; System.out.println(\"i think this line might cause a problem\"); } } of course, this would yield the compiler error. Test.java:7: unreachable statement I could understand why a warning might be justified as
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