unmarshalling

I'm trying to unmarshal an xml to an object using moxy.Below is the sample of the xml. <root> <name> <firstname>value</firstname> </name> <address>value of address</address> </root> And below is the class I'm trying to map. import javax.xml.bind.annotation.XmlAccessType; import javax.xml.bind.annotation.XmlAccessorType; import javax.xml.bind.annotation.XmlElement; import javax.xml.bind.annotation.XmlRootElement; import org.eclipse.persistence.oxm.annotations.XmlPath; @XmlRootElement(name="root") @XmlAccessorType(XmlAccessType.FIELD) public class Response { @XmlPath("name/firstname/text()")

I have an XML which is out of my control on how it is generated. I want to create an object out of it by unmarshaling it to a class written by hand by me. One snippet of its structure looks like: <categories> <key_0>aaa</key_0> <key_1>bbb</key_1> <key_2>ccc</key_2> </categories> How can I handle such cases? Of course the element count of is variable. If you use the following object model then each of the unmapped key_# elements will be kept as an instance of org.w3c.dom.Element: import java.util.List; import javax.xml.bind.annotation.XmlAnyElement; import javax.xml.bind.annotation

I'm using JAXB 2.2.2 to parse a simple XML-REST stream. This is the piece of code: JAXBContext jc = JAXBContext.newInstance( "com.example.entities" ); Unmarshaller u = jc.createUnmarshaller(); r = (Response )u.unmarshal( inputStream ); ObjectFactory class: @XmlRegistry public class ObjectFactory { public Response createRsp() { return new Response(); } } Response class: @XmlAccessorType(XmlAccessType.FIELD) @XmlRootElement(name="rsp") @XmlType public class Response { ... } The "com.example.entities" must contain the ObjectFactory class or jaxb.index. I would like to use the ObjectFactory class

I am looking at various approaches for marshalling/unmarshalling data between Scala and XML, and I'm interested in getting community feedback (preferably grounded in first-hand knowledge/experience). We're currently using JAXB, which is fine, but I'm hoping for a pure Scala solution. I'm considering the following approaches: Use Scala's built-in XML facilities : Scala->XML would be easy, but my guess is that the other direction would be fairly painful. On the other hand, this approach supports arbitrary translation logic. Data binding : scalaxb seems to be somewhat immature at the moment and

I am using Jersey 1.8 in my application. I am trying to consume POST data at the server. The data is of the type application/x-www-form-urlencoded . Is there a method to get all the data in one object, maybe a Map<String, Object> . I ran into Jersey's @Consumes(MediaType.APPLICATION_FORM_URLENCODED) . But using this would require me to use @FormParam , which can be tedious if the number of parameters are huge. Or maybe one way is this: @POST @Path("/urienodedeample") @Consumes(MediaType.APPLICATION_FORM_URLENCODED) @Produces(MediaType.APPLICATION_JSON) public Response uriEncodedExample(String