unmarshalling

Parsed SOAP response is different with the received response

為{幸葍}努か 提交于 2019-12-08 09:31:33
问题 I am trying to parse a SOAP response. I can show the full response using following line. System.out.println("Response: " + out.toString()); However when I parse the response and marshall the parsed response, it shows a wrong response. package-info.java @XmlSchema( namespace = "http://v3.hotel.wsapi.ean.com/", elementFormDefault = XmlNsForm.QUALIFIED) package com.ean; import javax.xml.bind.annotation.XmlNsForm; import javax.xml.bind.annotation.XmlSchema; My Code @XmlRootElement(name=

OpenSAML 3 unmarshaller is null

六月ゝ 毕业季﹏ 提交于 2019-12-08 08:24:22
问题 Hi i am currently porting an app to opensaml3 and run into the following issue: InitializationService.initialize(); ... Unmarshaller unmarshaller = Configuration.getUnmarshallerFactory().getUnmarshaller(qName); I have replaced the DefaultBootstrap from opensaml2 and previous by the initialize function. Still the factory is returning me null as marshaller. Any idea what is going wrong here? This is the output from initialize progress: [main] INFO org.opensaml.core.config.InitializationService

Jaxb unmarshal doesn't works

别说谁变了你拦得住时间么 提交于 2019-12-08 06:56:41
问题 I have this xml file: <?xml version="1.0" encoding="UTF-8"?> <diffgr:diffgram xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1" xmlns="http://tempuri.org/" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata"> <DocumentElement xmlns=""> <Result diffgr:id="Result1" msdata:rowOrder="0"> <CITY>York</CITY> </Result> </DocumentElement> </diffgr:diffgram> I have this java code: XMLInputFactory xif = XMLInputFactory.newFactory(); String content = readFile("D:\\work\\cim\\target\\my.xml",

Why don't DataOutputStream.writeChars(str) and String(byte[]) use the same encoding?

旧城冷巷雨未停 提交于 2019-12-08 06:30:20
问题 I'm writing some marshaling/unmarshaling routines for a class project and am a bit perplexed about Java's default behavior in this case. Here are my "naive" subroutines for writing and reading strings to and from byte streams: protected static void write(DataOutputStream dout, String str) throws IOException{ dout.writeInt(str.length()); dout.writeChars(str); } protected static String readString(DataInputStream din) throws IOException{ int strLength = 2*din.readInt(); // b/c there are two

How do JAXB handles attribute in tag?

橙三吉。 提交于 2019-12-08 06:07:14
问题 Suppose I have the following xml: <root> <tag1>value1</tag1> <tag2 attr1="somevalue"></tag2> </root> I want to know how the JAXB handles the attribute of any tag, when it converts from xml to any any object. (I mean when it does unmarshalling) 来源: https://stackoverflow.com/questions/10845484/how-do-jaxb-handles-attribute-in-tag

Unmarshalling SOAP Messages to java / or simply parsing SOAP message?

亡梦爱人 提交于 2019-12-08 05:36:12
问题 I am facing this problem for over than one month , so i would be realy pleased by your help , in fact i am asking about a way that can let me parse a SOAP message (request) to can retrieve the needed information , such as the security information if there is any and informations from the body of the message Thanks for answering me , but know i am dealing with another problerm which is the WS-SecurityPolicy and i have to finaly parse an xml file like this one : <?xml version="1.0" encoding=

Spring Web service unmarshalling not happening correctly

戏子无情 提交于 2019-12-08 03:18:27
问题 I have been trying to integrate the spring WS to test a SOAP webservice.Integration has hit a roadblock as I am not able receive the proper response in the unmarshelled object. Below are the details: Application Context is below: <!-- Define the SOAP version used by the WSDL --> <bean id="soapMessageFactory" class="org.springframework.ws.soap.saaj.SaajSoapMessageFactory"> <property name="soapVersion"> <util:constant static-field="org.springframework.ws.soap.SoapVersion.SOAP_12"/> </property>

Convert XML file into an XML object having a List [duplicate]

我们两清 提交于 2019-12-08 01:34:38
问题 This question already has answers here : Closed 6 years ago . Possible Duplicate: Best XML parser for Java How i can convert this xml file into an XML object? I have a XML like this . And i want to convert it into JAVA object. <P1> <CTS> Hello </CTS> <CTS> World </CTS> <P1> So I created following java classes with their properties. P1 class @XmlRootElement public class P1 { @XmlElement(name = "CTS") List<CTS> cts; } CTS class public class CTS { String ct; } Test Class File file = new File("D:

unexpected element error while unmarshalling

蓝咒 提交于 2019-12-07 17:58:02
问题 I should unmarshall simple xml as belo but getting error as Exception in thread "main" javax.xml.bind.UnmarshalException: unexpected element (uri:"http://example.com/service/response/v1", local:"WebResponse"). Expected elements are <{http://example.com/service/request/v1}WebResponse> at com.sun.xml.bind.v2.runtime.unmarshaller.UnmarshallingContext.handleEvent(UnmarshallingContext.java:603) I tried the solutions in this site but could not solve pls help. This is the xml present in response.xml

JAXB unmarshalling returns 'URI is not absolute' error

折月煮酒 提交于 2019-12-07 06:01:15
问题 I received following response from webservice, and am using following code to unmarshal the response, but it returns following error. SEVERE: java.lang.IllegalArgumentException: URI is not absolute Response <?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:soap="http://www.w3.org/2003/05/soap-envelope" xmlns:xsi="http://www.w3.org /2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soap:Body> <SearchFlightsResponse xmlns="ElsyArres.API"> <SoapMessage> <Username