uint8t | 易学教程

structs with uint8_t on a MCU without uint8_t datatype

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I am an Embedded Software developer and I want to interface to an external device. This device sends data via SPI. The structure of that data is predefined from the external device manufacturer and can't be edited. The manufacturer is providing some Header files with many typedefs of all the data send via SPI. The manufacturer also offers an API to handle the received packets in the correct way(I have access to the source of that API). Now to my problem: The typedefed structures contain many uint8_t datatypes. Unfortunately, our MCU doesn't support uint8_t datatypes, because the smallest type

Convert char* to uint8_t

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I transfer message trough a CAN protocol . To do so, the CAN message needs data of uint8_t type . So I need to convert my char* to uint8_t. With my research on this site, I produce this code : char* bufferSlidePressure = ui->canDataModifiableTableWidget->item(6,3)->text().toUtf8().data();//My char* /* Conversion */ uint8_t slidePressure [8]; sscanf(bufferSlidePressure,"%c", &slidePressure[0]); As you may see, my char* must fit in sliderPressure[0] . My problem is that even if I have no error during compilation, the data in slidePressure are totally incorrect . Indeed, I test it with a char* =

post training quantization for mobilenet V1 not working

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问题 I am trying to convert mobilenet V1 .pb file to quantized tflite file. I used the below command to do the quantization: tflite_convert \ --output_file=/home/wc/users/Mostafiz/TPU/models/mobilnet/test2_4thSep/mobilenetv1_test5.tflite \ --graph_def_file=/home/wc/users/Mostafiz/TPU/models/mobilnet/mobileNet_frozen_graph.pb \ --output_format=TFLITE \ --inference_type=QUANTIZED_UINT8 \ --inference_input_type=QUANTIZED_UINT8 \ --input_shape=1,224,224,3 \ --input_array=input \ --output_array

Convert byte array “[]uint8” to float64 in GoLang

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I'm trying to convert a []uint8 byte array into a float64 in GoLang. I can't find a solution for this issue online. I've seen suggestions of converting to a string first and then to a float64 but this doesn't seem to work, it loses it's value and I end up with zeroes. Example: metric.Value, _ = strconv.ParseFloat(string(column.Value), 64) And it doesn't work... For example, package main import ( "encoding/binary" "fmt" "math" ) func Float64frombytes(bytes []byte) float64 { bits := binary.LittleEndian.Uint64(bytes) float := math.Float64frombits(bits) return float } func Float64bytes(float

Convert char* to uint8_t

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问题 I transfer message trough a CAN protocol . To do so, the CAN message needs data of uint8_t type . So I need to convert my char* to uint8_t. With my research on this site, I produce this code : char* bufferSlidePressure = ui->canDataModifiableTableWidget->item(6,3)->text().toUtf8().data();//My char* /* Conversion */ uint8_t slidePressure [8]; sscanf(bufferSlidePressure,"%c", &slidePressure[0]); As you may see, my char* must fit in sliderPressure[0] . My problem is that even if I have no error

Convert byte array “[]uint8” to float64 in GoLang

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问题 I'm trying to convert a []uint8 byte array into a float64 in GoLang. I can't find a solution for this issue online. I've seen suggestions of converting to a string first and then to a float64 but this doesn't seem to work, it loses it's value and I end up with zeroes. Example: metric.Value, _ = strconv.ParseFloat(string(column.Value), 64) And it doesn't work... 回答1: For example, package main import ( "encoding/binary" "fmt" "math" ) func Float64frombytes(bytes []byte) float64 { bits := binary

reinterpret_cast between char* and std::uint8_t* - safe?

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问题 Now we all sometimes have to work with binary data. In C++ we work with sequences of bytes, and since the beginning char was the our building block. Defined to have sizeof of 1, it is the byte. And all library I/O functions use char by default. All is good but there was always a little concern, a little oddity that bugged some people - the number of bits in a byte is implementation-defined. So in C99, it was decided to introduce several typedefs to let the developers easily express themselves

When is uint8_t ≠ unsigned char?

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问题 According to C and C++, CHAR_BIT >= 8 . But whenever CHAR_BIT > 8 , uint8_t can\'t even be represented as 8 bits. It must be larger, because CHAR_BIT is the minimum number of bits for any data type on the system. On what kind of a system can uint8_t be legally defined to be a type other than unsigned char ? (If the answer is different for C and C++ then I\'d like to know both.) 回答1: If it exists, uint8_t must always have the same width as unsigned char . However, it need not be the same type;