uint8t

问题 I'm receiving the following Binary Stream from an HTTP request: HTTP REQUEST Document.get({id: $scope.documentId}, function(stream){ }); Angular Factory .factory('Document', ['$resource', 'DOCUMENTS_CONFIG', function($resource, DOCUMENTS_CONFIG) { return $resource(DOCUMENTS_CONFIG.DETAIL_URL, {}, { get: { method: 'GET', params: {}, url: DOCUMENTS_CONFIG.DETAIL_URL, isArray: false } }); } ]); Response console.log(stream) I need to convert this to a Uint8Array. I've tried to convert it to a

问题 I have an input which comes over UART. uint8_t uartRX_data[UART_RX_BUF_SIZE]=""; I need to pass this data to a function. And, in this function I want to compare it with predefined strings like: char RESP_OK[] = "OK"; char RESP_ERROR[] = "ERROR"; char RESP_FAIL[] = "FAIL"; What is the easiest way to do that? EDIT: My problem is only about the data comparison and data passing to a function. 回答1: As long as the string in uartRX_data is NULL terminated you should be able to use strcmp like so: if

问题 This question already has answers here : uint8_t can't be printed with cout (8 answers) Closed 5 years ago . A tiny piece of code drives me crazy but hopefully you can prevent me from jumping out of the window. Look here: #include <iostream> #include <cstdint> int main() { int8_t i = 65; int8_t j; std::cout << "i = " << i << std::endl; // the 'A' is ok, same as uchar std::cout << "Now type in a value for j (use 65 again): " << std::endl; std::cin >> j; std::cout << "j = " << j << std::endl;

问题 I am an Embedded Software developer and I want to interface to an external device. This device sends data via SPI. The structure of that data is predefined from the external device manufacturer and can't be edited. The manufacturer is providing some Header files with many typedefs of all the data send via SPI. The manufacturer also offers an API to handle the received packets in the correct way(I have access to the source of that API). Now to my problem: The typedefed structures contain many

问题 I am an Embedded Software developer and I want to interface to an external device. This device sends data via SPI. The structure of that data is predefined from the external device manufacturer and can't be edited. The manufacturer is providing some Header files with many typedefs of all the data send via SPI. The manufacturer also offers an API to handle the received packets in the correct way(I have access to the source of that API). Now to my problem: The typedefed structures contain many

问题 This question already has answers here : uint8_t iostream behavior (3 answers) Closed 6 years ago . $ file testfile.txt testfile.txt: ASCII text $ cat testfile.txt aaaabbbbccddef #include <iostream> #include <fstream> #include <string> #include <cstdint> typedef uint8_t byte; // <-------- interesting typedef std::basic_ifstream<byte> FileStreamT; static const std::string FILENAME = "testfile.txt"; int main(){ FileStreamT file(FILENAME, std::ifstream::in | std::ios::binary); if(!file.is_open()

问题 I have four uint8_t arrays: uint8_t arrayOne[12] = { 0x00,0x01,0x00,0x00,0x00,0x06,0xFE,0x03,0x01,0xC1,0x00,0x01 }; uint8_t arrayTwo[12] = { 0x00,0x01,0x00,0x00,0x00,0x06,0xFE,0x03,0x4E,0x2D,0x00,0x0C }; uint8_t arrayThree[12] = { 0x00,0x01,0x00,0x00,0x00,0x06,0xFE,0x03,0x01,0xF3,0x00,0x01 }; uint8_t arrayFour[12] = { 0x00,0x01,0x00,0x00,0x00,0x06,0xFE,0x03,0x20,0x04,0x00,0x01 }; I have added them to array: uint8_t *theArray[] = { arrayOne,arrayTwo,arrayThree,arrayFour }; now I want to pass

问题 I wrote the following code: #include <iostream> #include <iomanip> #include <stdint.h> using namespace std; int main() { uint8_t c; cin >> hex >> c; cout << dec << c; return 0; } But when I input c —hex for 12—the output is also c . I was expecting 12. Later I learned that: uint8_t is usually a typedef for unsigned char . So it's actually reading c as ASCII 0x63. Is there a 1 byte integer which behaves as an integer while doing I/O and not as char? 回答1: Not that I know of. You could do the I

问题 This question already has answers here : uint8_t can't be printed with cout (8 answers) Closed 5 years ago . A tiny piece of code drives me crazy but hopefully you can prevent me from jumping out of the window. Look here: #include <iostream> #include <cstdint> int main() { int8_t i = 65; int8_t j; std::cout << "i = " << i << std::endl; // the 'A' is ok, same as uchar std::cout << "Now type in a value for j (use 65 again): " << std::endl; std::cin >> j; std::cout << "j = " << j << std::endl;

问题 I have Swift code for convert this method: func DATA_TO_UINT8(_ d:Data) -> Array<UInt8> { return d.withUnsafeBytes { [UInt8](UnsafeBufferPointer(start: $0, count: (d.count))) } } and now i want it in Objective C . 回答1: To produce a stack based array try something like (code typed directly into answer, expect errors): NSData *data = ... UInt8 buf[data.length]; // local stack array [data getBytes:buf length:data.length]; If you want a heap array you will need to use malloc to allocate the