uid

问题 I got several uids like this: 10022, 10011, 1000 Actually I know the usernames of them are u0_a22 , u0_a11 , system . But the question is how can I get the username using codes? There is no /etc/passwd file at all.. 回答1: I wrote a utility class to get the UID/GID name by hardcoding values from android_filesystem_config.h. Usage: String uid = AndroidFilesystemConfig.getNameForId(1000); AndroidFilesystemConfig.java import android.os.Build; import android.util.SparseArray; import java.util

问题 I got several uids like this: 10022, 10011, 1000 Actually I know the usernames of them are u0_a22 , u0_a11 , system . But the question is how can I get the username using codes? There is no /etc/passwd file at all.. 回答1: I wrote a utility class to get the UID/GID name by hardcoding values from android_filesystem_config.h. Usage: String uid = AndroidFilesystemConfig.getNameForId(1000); AndroidFilesystemConfig.java import android.os.Build; import android.util.SparseArray; import java.util

问题 How can we generate unique id's between two JVMs running at the same time? I think UUID uuid = UUID.randomUUID(); or UID uid = new UID(); is not enough. 回答1: You can concat to UUID server ID so UUID will be unique in all servers 回答2: See UUID docs, you can follow the link to find the rfc4122 explaining how the UUID will be generated. The last 48 bits are concerning your question, the spacial unique node identifier confirming that this value will be a Universally Unique IDentifier . 4.1.2.

问题 How can we generate unique id's between two JVMs running at the same time? I think UUID uuid = UUID.randomUUID(); or UID uid = new UID(); is not enough. 回答1: You can concat to UUID server ID so UUID will be unique in all servers 回答2: See UUID docs, you can follow the link to find the rfc4122 explaining how the UUID will be generated. The last 48 bits are concerning your question, the spacial unique node identifier confirming that this value will be a Universally Unique IDentifier . 4.1.2.

问题 Im revisiting my database and noticed I had some primary keys that were of type INT. This wasn't unique enough so I thought I would have a guid. I come from a microsoft sql background and in the ssms you can choose type to "uniqeidentifier" and auto increment it. In mysql however Ive found that you have to make triggers that execute on insert for the tables you want to generate a guide id for. Example: Table: CREATE TABLE `tbl_test` ( `GUID` char(40) NOT NULL, `Name` varchar(50) NOT NULL,

问题 I have a Firebase Auth that stores the users, but it also builds a collection of users in the Cloud Firestore database. I can grab the users first name, but the problem I have is that it is always the last user that was added. here is my function in swift func welcomeName() { let db = Firestore.firestore() if let userId = Auth.auth().currentUser?.uid { var userName = db.collection("users").getDocuments() { (snapshot, error) in if let error = error { print("Error getting documents: \(error)")

问题 I'm building redis sentinal image that run.sh should run as non-rootuser run.sh while true; do master=$(redis-cli -h ${REDIS_SENTINEL_SERVICE_HOST} -p ${REDIS_SENTINEL_SERVICE_PORT} --csv SENTINEL get-master-addr-by-name mymaster | tr ',' ' ' | cut -d' ' -f1) if [[ -n ${master} ]]; then master="${master//\"}" else master=$(hostname -i) fi redis-cli -h ${master} INFO if [[ "$?" == "0" ]]; then break fi echo "Connecting to master failed. Waiting..." sleep 10 done sentinel_conf=/home/ubuntu

问题 When I just run adb shell , I get shell running from uid=2000(shell) gid=2000(shell) , without ptrace access to my application. How to open a shell with the same UID as launched application? 回答1: Use run-as <your package name> to switch to your app's UID or run-as <your package name> <command> to run a single command with your app's UID. 回答2: From this answer: The packages.xml file present in /data/system The packages.list file present in /data/system Contain the list of applications

问题 (null).1001.1001 What is this folder? Where does it come from? drwxrwxrwx 49 appusr appusr 4096 Jan 7 21:52 (null).1001.1001 I think it has something to do with Mr. Root impersonating Mr. AppUsr in a background task, but I posted to AskUbuntu last week, and nobody there recognized it. Why am I asking? Well ... On an Ubuntu box, I have a restricted-access applications user who is uid 1001 and gid 1001 . Root launches Rserve under that user during boot. The Rserve session is writing into a

问题 I am trying to build an android app in js that can detect eddystone beacons emitting UID. I followed this : https://evothings.com/detecting-eddystone-beacons-in-javascript-made-easy/ But I can only detect beacon html. I cannot find the line where you can look for UID. Does anyone has an idea ? 回答1: Are you sure your beacon is set to broadcast the Eddystone-UID packet? The thing to keep in mind is, Eddystone-UID and Eddystone-URL are two completely separate types of packets, and your beacon