Do we ignore overflow in Two's Complement
问题 I'm trying to wrap my head around overflow within twos complement for example say I'm trying to take away these two binary numbers: 1111 1000 0100 - 010 111 001 000 I convert the 2nd binary number to it's two complement equivalent and then simply add it but I noticed it resulted in an overflow of 1, do I simply ignore the overflow? or is there a rule I must follow 1111 1000 0100 + 1010 0011 1000 = (1) 1001 1011 1100 回答1: Short answer: if you are performing arithmetic on fixed-width binary