tty

问题 I'm a beginner in assembly (using nasm). I'm learning assembly through a college course. I'm trying to understand the behavior of the sys_read linux system call when it's invoked. Specifically, sys_read stops when it reads a new line or line feed . According to what I've been taught, this is true. This online tutorial article also affirms the fact/claim. When sys_read detects a linefeed, control returns to the program and the users input is located at the memory address you passed in ECX. I

问题 I'm a beginner in assembly (using nasm). I'm learning assembly through a college course. I'm trying to understand the behavior of the sys_read linux system call when it's invoked. Specifically, sys_read stops when it reads a new line or line feed . According to what I've been taught, this is true. This online tutorial article also affirms the fact/claim. When sys_read detects a linefeed, control returns to the program and the users input is located at the memory address you passed in ECX. I

问题 I'm a beginner in assembly (using nasm). I'm learning assembly through a college course. I'm trying to understand the behavior of the sys_read linux system call when it's invoked. Specifically, sys_read stops when it reads a new line or line feed . According to what I've been taught, this is true. This online tutorial article also affirms the fact/claim. When sys_read detects a linefeed, control returns to the program and the users input is located at the memory address you passed in ECX. I

问题 I am trying to do some work on a remote server using ssh--and ssh is called on the local machine from node.js A stripped down version of the script looks like this: var execSync = require("child_process").execSync; var command = 'ssh -qt user@remote.machine -- "sudo mv ./this.thing /to/here/;"'; execSync(command,callback); function callback(error,stdout,stderr) { if (error) { console.log(stderr); throw new Error(error,error.stack); } console.log(stdout); } I get the requiretty error sudo:

问题 I am trying to do some work on a remote server using ssh--and ssh is called on the local machine from node.js A stripped down version of the script looks like this: var execSync = require("child_process").execSync; var command = 'ssh -qt user@remote.machine -- "sudo mv ./this.thing /to/here/;"'; execSync(command,callback); function callback(error,stdout,stderr) { if (error) { console.log(stderr); throw new Error(error,error.stack); } console.log(stdout); } I get the requiretty error sudo:

问题 I'm using go's exec Run command to get command output, which works great when the command 'Stdout' field is set to os.Stdout , and the error is sent to os.Stderr . I want to display the output and the error output to the console, but I also want my program to see what the output was. I then made my own Writer type that did just that, wrote both to a buffer and printed to the terminal. Here's the problem—some applications change their output to something much less readable by humans when it

问题 I'm using go's exec Run command to get command output, which works great when the command 'Stdout' field is set to os.Stdout , and the error is sent to os.Stderr . I want to display the output and the error output to the console, but I also want my program to see what the output was. I then made my own Writer type that did just that, wrote both to a buffer and printed to the terminal. Here's the problem—some applications change their output to something much less readable by humans when it

问题 I use two Arduino Nano, and want to change their name as listed in /dev , because currently they are always ttyUSB<NUMBER> . How can I get a unique serial number to create a udev rule? I tried to get it via udevadm , but it returns the same serial ID for both Arduinos. /var/log: udevadm info -a -n /dev/ttyUSB0 | grep '{serial}' ATTRS{serial}=="0000:00:14.0" 回答1: Arduino Nano is based on ATmega328 which does not have a built-in USB controller. The USB connector on the board is connected to an

问题 Brief: there is huge Linux application with many child processes, and I need something like that: /* parent process, far from fork*/ suppress_child_output_to_parent_tty(); printf("important message"); /* huge piece of code */ printf("important message"); restore_child_output_to_parent_tty(); I know that exist a standard way to do this by make pipe, fork, redirect STDOUT to that pipe, select&read pipe /write to parent stdout at the some loop at different thread, manually pause this loop when

问题 I am implementing my own fragment of code for a security control purpose. It normally runs in the background but on a timeout needs to take over the current terminal, display a message, collect user input, and react to the user input. Waiting for the timeout is easy. Collecting user input while sleep is the active program is easy. Preventing the shell from stealing the user input I just tried to collect is not so easy. I am reasonably convinced that "What if two programs did this?" doesn't