tostring

深入理解javascript原型链 　　在javascript中原型和原型链是一个很神奇的东西，对于大多数人也是最难理解的一部分，掌握原型和原型链的本质是javascript进阶的重要一环。今天我分享一下我对javascript原型和原型链的理解。 一、对象等级划分 　　我们认为在javascript任何值或变量都是对象，但是我还需要将javascript中的对象分为一下几个等级。 　　首先Object是顶级公民，这个应该毋庸置疑，因为所有的对象都是间接或直接的通过它衍生的。Function是一等公民，下面会做解释。几个像String，Array，Date，Number，Boolean，Math等内建对象是二等公民。剩下的则都是低级公民。 　　 二、原型prototype 　　首先prototype是一个属性，同时它本身也是一个对象。那么哪些是具有prototype这个属性呢？其实javascript中所有的函数都有prototype这个属性，反过来所有具有prototype的对象本身也是一个函数，没错就是一个函数。 　　第一条我不再印证，主要看看第二条。大家都知道Object，Array，Date都有prototype，他们是函数吗？是的他们也是函数的一种，为什么这么说呢？我们在定义一个对象或者数组时，是不是可以这么做var o = new Object(),a = new

There are two ways to increase the usefulness of debugging information instead of seeing {MyNamespace.MyProject.MyClass} in the debugger. These are the use of the [DebuggerDisplayAttribute][1] and the ToString() method. using System.Diagnostics; ... [DebuggerDisplay("Name = {Name}")] public class Person { public string Name; } or public class Person { public string Name; public override string ToString() { return string.Format("Name = {0}", Name); } } Is there any reason to prefer one to the other? Any reason not to do both? Is it purely personal preference? Using [DebuggerDisplay] is meant

I want to format a string as a decimal, but the decimal contains some following zeros after the decimal. How do I format it such that those meaningless 0's disappear? string.Format("{0}", 1100M); string.Format("{0}", 1100.1M); string.Format("{0}", 1100.100M); string.Format("{0}", 1100.1000M); displays: 1100 1100.1 1100.100 1100.1000 but I want it to be: 1100 1100.1 1100.1 1100.1 For reference, here are other questions that are essentially duplicates of this, that I've found thanks to answers given here: Parse decimal and filter extra 0 on the right? Best way to display decimal without trailing

I'm taking a course on JavaScript but have no guide on toString method, what's the purpose of these two outputs in JavaScript: (35).toString(36) >>> "z" !!! (35).toString(37) >>> throws a RangeError !!! I am utterly confused as to why I am getting these results, I would really appreciate it if someone could shed some light on this. doubleOrt tldr: Number.prototype.toString can take an argument called radix that specifies the numeric base to use for the string representation of the number in question. Object.prototype.toString() An object's toString method is supposed to return a string

import java.util.ArrayList; public class Card { int number; String suit; public Card(int number, String suit) { this.number = number; this.suit = suit; @Override public String toString() { String[] high = { "Jack", "Queen", "King" }; String type; if (number < 10) { return String.valueOf(this.number) + " of " + this.suit; } else { return high[this.number-10] + " of " + this.suit; } //return suit + " of " + type; //return String.valueOf(number) + " of " + suit; } } public static void main(String[] args) { String[] suit = { "Clubs", "Diamonds", "Spades", "Hearts" }; // String[] high = { // "Jack"

I'm working on a program that converts numbers to words, but I'm having problems with the toString() method in the Numbers class. All the methods were given to me, so I could implement; therefore, I can't remove any of them... number: 4564 --> four thousand and five hundred and sixty four here's the code Numbers class package numberstowords; import java.util.*; public class Numbers { //array containing single digits words numbers:0-9 private final String[] SINGLE_DIGITS_WORDS; //array containing special words words eg:10-19 private final String[] TEEN_DIGITS_WORDS; //array containing tens

This question is from an assignment. I have to override a toString() method in a class that creates a circularly linked list and I actually have a toString() method that works great, it passes all of my tests everything. So my project is autograded and it apparently doesn't approve of my method 100%. So my question is: is there a better way to write this toString() method that would be more efficient? public String toString() { if (size == 0) { return "[]"; } else { String output = ""; Node<E> tempNode = actualElement; while (tempNode.next() != actualElement) { if (output.equals("")) { output

JS 变量类型 JS中有 6 种原始值，分别是： boolean number string undefined symbol null 引用类型： 对象 数组 函数 JS中使用typeof能得到哪些类型？ 其中一个奇怪的 null，虽然是基本变量，但是因为设计的时候 null 是全0，而对象是 000 开头，所以有这个误判。 boolean number string undefined symbol object function bigint instanceof 能正确判断对象的原理是什么？ 判断一个对象与构造函数是否在一个原型链上 const Person = function() {} const p1 = new Person() p1 instanceof Person // true var str = 'hello world' str instanceof String // false var str1 = new String('hello world') str1 instanceof String // true 实现一个类型判断函数 判断null 判断基础类型 使用 Object.prototype.toString.call(target) 来判断 引用类型 注意： 一定是使用 call 来调用，不然是判断的Object.prototype的类型