How do I format a C# decimal to remove extra following 0's?

Question

I want to format a string as a decimal, but the decimal contains some following zeros after the decimal. How do I format it such that those meaningless 0's disappear?

string.Format("{0}", 1100M);
string.Format("{0}", 1100.1M);
string.Format("{0}", 1100.100M);
string.Format("{0}", 1100.1000M);

displays:

1100
1100.1
1100.100
1100.1000

but I want it to be:

1100
1100.1
1100.1
1100.1

For reference, here are other questions that are essentially duplicates of this, that I've found thanks to answers given here:

• Parse decimal and filter extra 0 on the right?
• Best way to display decimal without trailing zeroes
• How can I strip zeros and decimal points off of decimal strings?

Answer 1

You can use ToString() with the General ("G") Format Specifier to achieve the desired result. Trailing zeros are truncated when using this format string with a precision specified. In order to prevent rounding in any situations, you will need to set the precision to the maximum allowed for decimals (29).

The line of code to produce what you want is number.ToString("G29"), where number is your original decimal.

Be aware that any numbers smaller than 0.0001 will be converted to scientific notation. More details on how this formatter works can be found at the reference link above.

Answer 2

string s = d.ToString("0.#############################");

Answer 3

They're not necessarily meaningless - they indicate the precision during calculation. Decimals maintain their precision level, rather than being normalized.

I have some code in this answer which will return a normalized value - you could use that, and then format the result. For example:

using System;
using System.Numerics;

class Test
{
    static void Display(decimal d)
    {
        d = d.Normalize(); // Using extension method from other post
        Console.WriteLine(d);
    }

    static void Main(string[] args)
    {
        Display(123.4567890000m); // Prints 123.456789
        Display(123.100m);        // Prints 123.1
        Display(123.000m);        // Prints 123
        Display(123.4567891234m); // Prints 123.4567891234
    }
}

I suspect that most of the format string approaches will fail. I would guess that a format string of "0." and then 28 # characters would work, but it would be very ugly...

Answer 4

You can specify the format string like this:

String.Format("{0:0.000}", x);

Answer 5

How about:

string FormatDecimal(decimal d)
{
    const char point = System.Globalization.NumberFormatInfo.CurrentInfo.NumberDecimalSeparator[0];
    string s = d.ToString();
    // if there's no decimal point, there's nothing to trim
    if (!s.Contains(point) == -1)
        return s;
    // trim any trailing 0s, followed by the decimal point if necessary
    return s.TrimEnd('0').TrimEnd(point);
}

Answer 6

Unlike what everybody suggest to use a G format specifier I would suggest the following to preserve both thousand separator and decimal point while removing extra trailing zeros:

{0:#,#.##}

The result of this format is much better than G in most cases:

String.Format("{0:#,#.##}",25/2.4);
10.42

String.Format("{0:#,#.##}",1000000);
1,000,000

String.Format("{0:#,#.##}",1000000.3600000);
1,000,000.36

And the G specifier can't really handle all the possible combinations:

String.Format("{0:G29}",25/2.4);
10.416666666666668

String.Format("{0:G2}",25/2.4);
10

String.Format("{0:G29}",1000000.3600000);
1000000.36

String.Format("{0:G2}",1000000.3600000);
1E+06

Answer 7

Quite a few answers already. I often refer to this cheat sheet: http://blog.stevex.net/string-formatting-in-csharp/

Answer 8

Somewhat hackish, but this should work:

decimal a = 100.00M;
string strNumber = string.Format("{0}", a);
Console.WriteLine(strNumber.Contains('.') ? strNumber.TrimEnd('0').TrimEnd('.') : strNumber);

Answer 9

I believe you want to do:

var s = String.Format("{0:#####.###}");

Answer 10

String.Format("{0:0.##}", 123.0); // "123"

Answer 11

double a = 1100.00
double  b =1100.1
double  c = 1100.100
double  d =1100.1000

Remove last zero after point


string stra = a.toString("0.00").TrimEnd('0').TrimEnd('.');
string strb = b.toString("0.00").TrimEnd('0').TrimEnd('.');
string strc = c.toString("0.00").TrimEnd('0').TrimEnd('.');
string strd = d.toString("0.00").TrimEnd('0').TrimEnd('.');

Output

1100
1100.1
1100.1
1100.1