tostring

lxml.etree fromsting() and tostring() are not returning the same data

家住魔仙堡 提交于 2019-12-07 14:26:37
问题 I'm learning lxml (after using ElementTree) and I'm baffled why .fromstring and .tostring do not appear to be reversible. Here's my example: import lxml.etree as ET f = open('somefile.xml','r') data = f.read() tree_in = ET.fromstring(data) tree_out = ET.tostring(tree_in) f2 = open('samefile.xml','w') f2.write(tree_out) f2.close 'somefile.xml' was 132 KB. 'samefile.xml' - the output - was 113 KB, and it is missing the end of the file at some arbirtrary point. The closing tags of the overall

Why does Arrays.toString(values).trim() produce [bracketed text]?

徘徊边缘 提交于 2019-12-07 12:33:38
问题 Map<String, String[]> map = request.getParameterMap(); for (Entry<String, String[]> entry : map.entrySet()) { String name = entry.getKey(); String[] values = entry.getValue(); String valuesStr = Arrays.toString(values).trim(); LOGGER.warn(valuesStr); I'm trying to look at a request parameter value using the code above. Why does Arrays.toString(values).trim(); bracket the parameter value so it looks like this: [Georgio] What's the best way to get the String here without the brackets? If I do

C# XMLElement.OuterXML in a single line rather than format

依然范特西╮ 提交于 2019-12-07 10:39:13
问题 I am trying to log some XML responses from a WCF Service using log4net. I want the output of the XML file to the log to be in properly formed XML. The request comes in as an XMLElement. Example: The request comes in as this: <?xml version="1.0" encoding="utf-8"?> <ApplicationEvent xmlns="http://courts.wa.gov/INH_TV/ApplicationEvent.xsd"> <Severity xmlns="">Information</Severity> <Application xmlns="">Application1</Application> <Category xmlns="">Timings</Category> <EventID xmlns="">1000<

C# increment ToString

假如想象 提交于 2019-12-07 05:58:24
问题 I add an unexpected behaviour from C#/WPF private void ButtonUp_Click(object sender, RoutedEventArgs e) { int quant; if( int.TryParse(Qnt.Text, out quant)) { string s = ((quant++).ToString()); Qnt.Text = s; } } So, if I get quant as 1, quant will be incremented to 2. But the s string will be 1. Is this a question of precedence? EDIT: I re-wrote this as: quant++; Qnt.Text = quant.ToString(); and now this works as I expected. 回答1: You are using the post -increment operator. This evalutates to

Why is System.out.println(super) not permitted?

倖福魔咒の 提交于 2019-12-07 03:26:54
问题 Why is System.out.println(super) not permitted? System.out.println(this); This is OK and this.toString() is called and printed automatically. Of course, instance variable is OK instead of this . However, this and super can be used in same way as I know. System.out.println(super); So why does this fail? I think it's supposed to call super.toString() implicitly. I have read Java specification document, but I haven't found the reason. 回答1: Implementing a standalone variant of super that breaks

浅谈JS的toString

我怕爱的太早我们不能终老 提交于 2019-12-06 22:30:37
任何一个对象都有toString()方法(默认继承自Object,自己可以重写),此方法返回一个字符串。 var sayYo = function () { alert("sayYo2!"); } console.log(sayYo); 输出打印值为函数体 科普: 实际打印的是: sayYo.toStirng() , toString 默认打印函数体,当然你可以覆盖这个函数: Function.prototype.toString = function(){ //你想打印的东西 } var sayYo = function () { alert("sayYo2!"); } console.log(sayYo); 此时打印如下 调整如下 . 来源: https://www.cnblogs.com/jianxian/p/11999882.html

AS3: Can ByteArray return its content as a string with two bytes per unicode character?

最后都变了- 提交于 2019-12-06 20:40:32
var bytes:ByteArray = new ByteArray; bytes.writeInt(0); trace(bytes.length); // prints 4 trace(bytes.toString().length); // prints 4 When I run the above code the output suggests that every character in the string returned by toString contains one byte from the ByteArray. This is of course great if you want to display the content of the ByteArray, but not so great if you want to send its content encoded in a string and the size of the string matters. Is it possible to get a string from the ByteArray where every character in the string contains two bytes from the ByteArray? You can reinterpret

Java 开发之 Lombok 必知必会

做~自己de王妃 提交于 2019-12-06 16:26:23
转载链接地址: https://juejin.im/post/5cf3edf7e51d454f71439c79 1. 前言 在目前众多编程语言中,Java 语言的表现还是抢眼,不论是企业级服务端开发,还是 Andorid 客户端开发,都是作为开发语言的首选,甚至在大数据开发领域,Java 语言也能占有一席之地,如 Hadoop,Spark,Flink 大数据等。而作为已经诞生 24 年的 Java 相比其他语言来说,编写起来略显得冗长和复杂,而为了能极大提升 Java 开发的效率和代码简洁性,一个 Java 库 Lombok 就这样诞生了。 首先我们还是看下 Lombok 官方的描述: Project Lombok is a java library that automatically plugs into your editor and build tools, spicing up your java. Never write another getter or equals method again, with one annotation your class has a fully featured builder, Automate your logging variables, and much more. 从上面的说明里我们可以初步认识一下 Lombok

Forcing Java 8 LocalTime toString to report omitted values

微笑、不失礼 提交于 2019-12-06 15:26:02
I have the following datetime helper method that converts a UTC-zoned Java 8 Date into a datetime string: public static String dateTimeString(Date date) { return date.toInstant().atZone(ZoneId.of("UTC")).toLocalDateTime().toString(); } The desired result is to always have the resultant String be formatted as: YYYY-MM-dd'T'HH:mm:ss'Z' Problem is, Java 8 LocalTime#toString() intentionally strips off time components that are zero. So for instance if I have a Date instance that represents June 8, 2018 at 12:35:00 UTC . Then the output of this method above is: 2018-06-08'T'12:35'Z' . Whereas I want

Why do I need to override ToString?

江枫思渺然 提交于 2019-12-06 09:15:35
I'm a beginner to c# programming and recently started working on a bachelors degree. What I'm trying to say is, I'm new. I have marked the place where I have the problem. The problem is that I don't understand why I need to put override in the code at all. There is 2 var of the type object (first and rest). public Pair() { first = rest = null; } public Pair(Object o) { first = o; rest = null; } public Object First() { return(first); } public Object Rest() { return(rest); } public Pair Connect(Object o) { rest = o; return(this); } //Here is the "override string ToString" I don't understand. Why