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Open clicked tab and close the rest

由 ▼魔方 西西 提交于 2020-06-17 09:38:19
问题 I'm using JQuery to adjust some accordions. I have the accordion logic ready, but can't get the desired result. I would like that when a tab is clicked, that particular tab opens and the others close if they are open. And if an open tab is clicked, that particular tab closes too. So at any given time, only one tab should be open, but all tabs can be closed. Here is the fiddle https://jsfiddle.net/4d5mjgza/ $(function() { $('.collapsible-trigger').on('click', function() { var panel = $(this)

Open clicked tab and close the rest

由 你离开我真会死。 提交于 2020-06-17 09:38:09
问题 I'm using JQuery to adjust some accordions. I have the accordion logic ready, but can't get the desired result. I would like that when a tab is clicked, that particular tab opens and the others close if they are open. And if an open tab is clicked, that particular tab closes too. So at any given time, only one tab should be open, but all tabs can be closed. Here is the fiddle https://jsfiddle.net/4d5mjgza/ $(function() { $('.collapsible-trigger').on('click', function() { var panel = $(this)

Toggle two components using react hooks

由 二次信任 提交于 2020-06-01 05:07:47
问题 I have two instances of the same component. The component can be opened or closed. Component has const [isOpen, setIsOpen] = useState(false) which is being set using useCallback const openComponent = useCallback(() => { setIsOpen(true) }, []) const closeComponent = useCallback(() => { setIsOpen(false) }, []) Components are within their own context. But I have trouble even coming up with an idea how to handle via parent, when one instance opens, close the other conundrum. Passing state to

How to toggle/switch class of a div onclick using only javascript

由 你。 提交于 2020-05-11 02:54:40
问题 I want a div to switch its class (toggle) onclick and then revert back to original class onclick again My code is: function myfunc() { //the code over here } .normal { width:25%; height:25%; background: #f00; } .active { width:100%; height:100%; background: #f00; } #div{} <body> <div id="div" onclick="myfunc()">click here</div> </body> 回答1: using pure js: <div id="div" class="normal" onclick="myfunc(this)">click here</div> js function myfunc(div) { var className = div.getAttribute("class");

Reading values from list of toggles in SwiftUI

由 我是研究僧i 提交于 2020-04-17 07:17:49
问题 I hope this question isn't too stupid. I'm stuck with this problem for a long time now, tried different approaches and I'm still failing. I'm quite new to Swift and SwiftUI, that's why maybe I don't see the obvious. I have a View which contains of a List of toggles. The toggle list relies on setData which is built from a JSON-file which contains an id, a name and an imageUrl. In this view the user is able to select different sets to start a game with: import SwiftUI struct GameGenerationView:

(Swift) How to hide some sections in tableView when toggle switch is on?

由 人走茶凉 提交于 2020-03-26 03:26:11
问题 I have 5 tebleView sections, code is mostly the same for each of them. Main difference is in cell.labelCell.text : CellForRow method: let cell = tableView.dequeueReusableCell(withIdentifier: "ToggleTableViewCell", for: indexPath) as! ToggleTableViewCell cell.cellSwitch.setOn(false, animated: false) switch (indexPath.section, indexPath.row) { case (1,0): cell.labelCell.text = "Section 1" cell.callback = { [unowned self] check in UIView.transition(with: tableView, duration: 0.5, options:

[译]迁移到新的 React Context Api

由 强颜欢笑 提交于 2020-03-22 22:25:50
随着 React 16.3.0 的发布，context api 也有了很大的更新。我已经从旧版的 api 更新到了新版。这里就分享一下我（作者）的心得体会。 回顾 下面是一个展示如何使用旧版 api 的例子： function Usage(props) { return ( <Toggle onToggle={props.onToggle}> <Toggle.On>The button is on</Toggle.On> <Toggle.Off>The button is off</Toggle.Off> <div> <Toggle.Button /> </div> </Toggle> ) } 上面的代码会返回一个复合组件 Toggle 。这个组件可以让子组件共享隐式的状态。在某些简单的情况下可以用 React.Children.map 来处理。但是，这个例子需要使用 context api 来达到在 React 的某个组件树的任意节点分享 state 的目的。 旧的 Context Api 这是一个旧版 context api 的应用例子： const TOGGLE_CONTEXT = "__toggle__"; // Toggle on function ToggleOn({ children }, context) { const { on } = context

jQuery toggle and IF visible

由 最后都变了- 提交于 2020-03-17 10:28:11
问题 I have a div which contains settings and options on an account management page. $("#moreOptions").slideToggle('slow'); if ($("#moreOptions").is(":visible") == true) { $("#lnkMoreOpt").text("Less Options «") } else { $("#lnkMoreOpt").text("More Options »") } The code above should change the text of the more/less options link depending on whether it is visible or not, however it appears jQuery does not treat toggling as making it invisible/visible. How can I implement this while still using the

Toggle

由 ﹥＞﹥吖頭↗ 提交于 2020-03-09 20:00:37
public class demo : MonoBehaviour { public Texture texture; private bool textBool = false;toggle private bool textureBool = true; private void OnGUI() { if (!texture) { //判断图片是否参加 Debug.LogWarning("请添加一张图片"); return; } textBool=GUI.Toggle(new Rect(Screen.width / 8.5f, Screen.height / 7, Screen.height / 5, Screen.height / 5),textBool,"开关控件"); textureBool=GUI.Toggle(new Rect(Screen.width / 4, Screen.height / 7, Screen.height / 5, Screen.height / 5),textureBool,texture); } } 来源： https://www.cnblogs.com/zyz322/p/12450399.html

SwiftUI - usage of toggles - console logs: “invalid mode 'kCFRunLoopCommonModes'” - didSet does not work

由 放肆的年华 提交于 2020-03-03 09:43:40
问题 I have a general problem using toggles with SwiftUI. Whenever I use them I get this console error: invalid mode 'kCFRunLoopCommonModes' provided to CFRunLoopRunSpecific - break on _CFRunLoopError_RunCalledWithInvalidMode to debug. This message will only appear once per execution. In addition to this didSet does not print anything when I hit the toggle in the simulator. Does anyone have an idea, or is it a SwiftUI bug? Other related questions on StackOverflow which are some month old didn't
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