time

Simple <Time.h> program takes large amount CPU

一笑奈何 提交于 2021-02-17 07:08:06
问题 I was trying to familiarize myself with the C time.h library by writing something simple in VS. The following code simply prints the value of x added to itself every two seconds: int main() { time_t start = time(NULL); time_t clock = time(NULL); time_t clockTemp = time(NULL); //temporary clock int x = 1; //program will continue for a minute (60 sec) while (clock <= start + 58) { clockTemp = time(NULL); if (clockTemp >= clock + 2) { //if 2 seconds has passed clock = clockTemp; x = ADD(x);

How to display time amount to user?

我怕爱的太早我们不能终老 提交于 2021-02-17 04:45:44
问题 I want to convert time amount from milli-sec to a human readable string. For example: 3,600,000 should be displayed as 1:00:00 (1 hour). Is there an existing library or class in Java that can do that? 回答1: Since 1.5 there is the java.util.concurrent.TimeUnit class, use it like this: String.format("%d min, %d sec", TimeUnit.MILLISECONDS.toMinutes(millis), TimeUnit.MILLISECONDS.toSeconds(millis) - TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millis)) ); For Versions below 1.5 You

How to sort object array by time in javascript

时间秒杀一切 提交于 2021-02-17 02:38:07
问题 I have a object array looking something like this: [0] = { transportnumber: '45', time: '10:28:00', date:"2017-01-16"} [1] = { transportnumber: '45', time: '10:38:00', date:"2017-01-16"} [2] = { transportnumber: '45', time: '10:48:00', date:"2017-01-16"} [3] = { transportnumber: '14', time: '10:12:00', date:"2017-01-16"} [4] = { transportnumber: '14', time: '10:24:00', date:"2017-01-16"} [5] = { transportnumber: '14', time: '10:52:00', date:"2017-01-16"} The object array will always look like

How to read from the two same dates without input the time

懵懂的女人 提交于 2021-02-17 02:07:48
问题 I have a query like below. SELECT occupation AS 'Contact occupation', sum(total) AS 'Quantity' FROM ( SELECT CASE WHEN contacts.occupation IS NULL THEN 'Other' WHEN trim(contacts.occupation) = '' THEN 'Other' ELSE contacts.occupation END AS occupation, count(DISTINCT(concat(patients.id, '-', individual_appointments.practitioner_id))) AS total FROM individual_appointments JOIN patients ON patients.id = individual_appointments.patient_id JOIN practitioners ON practitioners.id = individual

Java current time different values in api

强颜欢笑 提交于 2021-02-16 14:57:50
问题 I'm a little confused using the DateTime related class for Java SE 7 and 8 API's, for displaying the current time, I'm reviewing the multiple ways for get the system's current datetime. My question is : Which one is more accurate for displaying time in millis? Next is the code snippet, I'm using Java 8 for the reviewing. import java.time.Instant; import java.util.Calendar; import java.util.Date; public class CurrentTimeValidationDemo { public static void main(String[] args) { Instant now =

Java current time different values in api

坚强是说给别人听的谎言 提交于 2021-02-16 14:57:43
问题 I'm a little confused using the DateTime related class for Java SE 7 and 8 API's, for displaying the current time, I'm reviewing the multiple ways for get the system's current datetime. My question is : Which one is more accurate for displaying time in millis? Next is the code snippet, I'm using Java 8 for the reviewing. import java.time.Instant; import java.util.Calendar; import java.util.Date; public class CurrentTimeValidationDemo { public static void main(String[] args) { Instant now =

How do I include a timezone in my d3 time formatted data?

我是研究僧i 提交于 2021-02-13 17:26:49
问题 I"m using d3 v4. My x-axis data consists of time in milliseconds (since 1970). I would like to display this as eastern standard time, for example 08/09/17 5:20 PM EDT so I tried focus.select("text").text(d.value).append("tspan") .attr("x", 10).attr("dy", "1.5em").text(d3.timeFormat("%m/%d/%Y %H:%M %p %Z+5")(d.index_date)); but unfortunately it is instead displaying as 08/09/17 5:20 PM -0500 +% What's the proper way to format the date/time as EDT (US Eastern standard time)? 回答1: D3 v4 time

How to remove timezone when convert from Date to DateTime

纵饮孤独 提交于 2021-02-11 17:19:27
问题 I have a Date get from Database and I want convert it to DateTime and set it to begin day. I write it below: Date fromDate = studentDateJoin.getDate(); //result: fromDate = Mon Jan 01 00:00:02 ICT 2018 //convert to DateTime DateTime newDate = new DateTime(fromDate); But when I convert it add time zone after convert. newDate look like : newDate = 2018-01-01T14:13:04.574Z+7 I have a question: How to convert it to begin day and remove timezone: Example I want to convert it look like: //Convert

Is there any way by which I can get TimeZone value using time stamp

人走茶凉 提交于 2021-02-11 15:40:38
问题 This is the value which I have, Sun Mar 29 2020 02:55:00 GMT+0530 and I want to get,for example Asia/Calcutta as ouput. Thanks in advance. 回答1: Offset does not indicate zone get TimeZone value using time stamp No. You cannot determine a time zone from an offset. Many time zones can share the same offset-from-UTC (the number of hours-minutes-seconds ahead or behind the prime meridian). See the list of time zone names in Wikipedia. Click on the column header to sort by offset. Notice how often

Time formatting: how to write a While loop that operates for a whole minute?

北城以北 提交于 2021-02-11 14:40:50
问题 I have written the following function: iterations_per_minute = function() { Sys.setenv(TZ='GMT+5') ## This line is optional; it just sets my timezone final_instant = as.numeric(format(Sys.time(), "%H.%M")) + 0.01 counter = 0 while(as.numeric(format(Sys.time(), "%H.%M")) < final_instant) { counter = counter + 1 } return(counter) } You can infer from the code what the function does, but allow me to explain in lay words anyway: what number can you reach by counting as fast as possible during one